As shown in the figure, C is the midpoint of line AB, point D is on line CB, ad = 4, BD = 2, find the length of line CD

As shown in the figure, C is the midpoint of line AB, point D is on line CB, ad = 4, BD = 2, find the length of line CD

CD+BD=BC AD+BD=AB=6 BC=AB/2=3 CD=BC-BD=3-2=1

As shown in Figure 1, the line segments AB and CD intersect at point O and connect AD and CB. We call the figure in Figure 1 "figure 8". As shown in Figure 2, under the condition of Figure 1, the bisectors AP and CP of ∠ DAB and ∠ BCD intersect at point P, and intersect with CD and ab at M and N, respectively
Label: DAB bisection, DAB, CP
(1) In Figure 1, please write directly the quantitative relationship among ∠ a, ∠ B, ∠ C, ∠ D:;
(2) If you look carefully, in Figure 2, the number of "8-shaped" is: 1;
(3) In Figure 2, if ∠ d = 400 and ∠ B = 360, try to find the degree of ∠ P;
(4) If ∠ D and ∠ B are arbitrary angles in Figure 2, and other conditions remain unchanged, what is the quantitative relationship between ∠ P and ∠ D and ∠ B

Given the line AB = a, extend Ba to point C so that AC = 2 / 1ab and point D is the midpoint of line BC. (1) find the length of AC; (2) if ad = 3cm, find the length of ab
Given the line AB = a, extend Ba to point C so that AC = 2 / 1ab and point D is the midpoint of line BC
(1) Seeking the length of AC
(2) If ad = 3cm, find the length of ab

AC=0.5AB=0.5a
Ad = (2 / 3-1 / 2) BC = 1 / 6BC, so BC = 18cm, ab = 2 / 3bC = 12cm

As shown in the figure, it is known that in △ ABC, BC = 4cm, point D is on AC, and BD = Ba, e and F are the midpoint of BC and ad respectively. Connect EF and find the length of line EF

It can be seen from the drawing that ∠ AFB is 90 degrees, that is, △ BFC is a right triangle, ∵ e is the midpoint of BC, ∵ EF = 1 / 2, be = 2

As shown in the figure, given the line segment AB = 2cm, extend Ba to point C so that BC = 2Ab, take the midpoint g of line segment AC, and calculate the length of line segment BG

C—G—A——B
∵AB＝2,BC＝1AB
∴AC＝BC-AB＝2AB-AB＝AB＝2
∵ G is the midpoint of AC
∴AG＝AC/2＝2/2＝1
∴BG＝AG+AB＝1+2＝3(cm)
The math group answered your question,

As shown in the figure, given the line AB = a, extend Ba to point C so that AC = 1 AB 3 / 3, and point D is the midpoint of line BC to find the length of CD

(AB + 1 AB / 3) △ 2 = 2 AB / 3

As shown in the figure, given that Ba is perpendicular to AC and ad is perpendicular to BC, the distance from point C to AB in the figure is a line segment

It's AC. you can draw a picture

As shown in Figure 11, draw and calculate: extend line AB to D to make AB = 2bd, and then extend line Ba to point C to make ad = AC
(1) How many times is the line CD of ad? (2) how many parts is the line BC of CD
------------------------------
A B

Let the length of BD segment be unit one, then AB2,
AD=2+1=3,
AC is three,
CD=3+3=6.
CD is 2 times of AD, BC = 3 + 2 = 5
5 / 6 is BC / CD

If the segment AB is extended to C to make BC = 2Ab, and then Ba is extended to D to make ad = 1 / 2Ab, then CD: BD =?

7:3

Extend line AB to C so that BC = 2Ab and point D is the midpoint of AC. if DB = 5cm, then AC = () cm

Let AB = x, then BC = 2x
Since D is the midpoint of line AC, ad = 1.5x
Ad = AB + BD, BD = 5
So 1.5x = x + 5
x=10
So AC = AB = + BC = x + 2x = 3x = 30