Let the eigenvalues of the fourth-order square matrix a be 1 / 2,1 / 3,1 / 4,1 / 5, then | a ^ - 1-e | =?

Let the eigenvalues of the fourth-order square matrix a be 1 / 2,1 / 3,1 / 4,1 / 5, then | a ^ - 1-e | =?


The eigenvalues of a ^ - 1-e are (1 / λ - 1): 1,2,3,4
So the determinant is 1 * 2 * 3 * 4 = 24



Let a be a square matrix of order 3 and its eigenvalues be 3, - 1,2, then | a ^ 2 + E|=





Let the three eigenvalues of the third order square matrix a be 1,2,3, then the three eigenvalues of 6A * are


A*=|A|A^(-1)
|A|=1×2×3=6
A*=6A^(-1)
therefore
The characteristic value is
6×1/1=6
6×1/2=3
6×1/3=2