If the lengths of the two sides of an isosceles triangle are 4 and 6 respectively, find the height of the bottom edge

If the lengths of the two sides of an isosceles triangle are 4 and 6 respectively, find the height of the bottom edge

6 waist, 4 base, height = root (36-4) = 4 root 2
4 waist, 6 base, height = root (16-9) = root 7

If the lengths of the two sides of an isosceles triangle are 4 and 6, then the height of the bottom is ()
A. 42 or 7b. 7 or 41c. 42d. 7

∵ AB = AC, ad ⊥ BC, ∵ BD = CD, there are 4, 4, 6 and 4, 6, 6 cases of isosceles triangle with side length 4 and 6. ① when it is 4, 4 and 6, the high ad on the bottom edge is AB2 − BD2 = 42 − 32 = 7; ② when it is 4, 6 and 6, the high ad on the bottom edge is 62 − 22 = 42

If both sides of an isosceles triangle are 4 and 6, then the area of the triangle

There are two situations
1. If the waist length is 4, then the height = root 4, square - 3, square = root 7, and the area is equal to 1 / 2 * 6 * root 7 = 3, root 7;
2. If the waist length is 6, then the height = root 6 square - 2 square = 4 root 2, the area is equal to 1 / 2 * 4 root 2 = 8 root 2
Answer: area is 3 7 or 8 2 square units