It is known that one root of the equation x ^ 2 + KX + 3 = 0 is - 1

It is known that one root of the equation x ^ 2 + KX + 3 = 0 is - 1

If x = - 1
1-k+3=0
4-k=0
We get k = 4
therefore
The equation is
x²+4x+3=0
(x+3)(x+1)=0
Get x = - 1 or x = - 3
The other is x = - 3

The equation 3 (x-1) = KX + 14 of X has a positive integer solution, and the integer k =?

3 (x-1) = KX + 14 3x-3-kx-14 = 0 (3-K) x = 17 x = 17 / (3-K) so equation 3 (x-1) = KX + 14 has integer solution, then 17 / (3-K) is an integer, so K can only be - 14 or 20, and the integer solution is 1 or - 1

If the two roots of the equation x2 + kx-6 = 0 are integers, then the value of K is equal to-----

Equal to 1 or - 1 or 5 or - 5