Simplify (1 + Cos2 α) / (3sin2 α) * (2sin2 α) / (COS α) to be equal to

Simplify (1 + Cos2 α) / (3sin2 α) * (2sin2 α) / (COS α) to be equal to

If A-B = π / 6, Tana tanb = 2 √ 3 / 3, find tanatanb=

tan(A-B)=(tanA-tanB)/[1+tanAtanB]=√3/3
2√3/3/[1+tanAtanB]=√3/3
2/[1+tanAtanB]=1
1+tanAtanB=2
tanAtanB=1

In △ ABC, C = 120 ° Tana + tanb = (2 radical sign 3) △ 3, find cosacosb

Answer 3 / 4

If (1 + Tana) (1 + tanb) = 4 and a and B are acute angles, then a + B =?

Take this formula apart and get Tana + tanb + Tana * tanb = 3, because a and B are acute angles, so tanb = Tan (90-a) = COTA, so Tana * tanb = 1, so Tana + tanb = 2.. that is, Tana + COTA = 2.. because Tana + COTA is greater than or equal to 2, only when a = Pai / 4, we take the equal sign, so B = Pai / 4. So a + B = Pai /

If a = 20 ° and B = 25 °, then the value of (1 + Tana) (1 + tanb) is?

Tan [a + b] = (Tan [a] + Tan [b]) / (1-tan [a] Tan [b]) = Tan [45] = 1, that is, 1-tan [a] Tan [b] = Tan [a] + Tan [b]; so the original formula is 1 + (Tan [a] + Tan [b]) + Tan [a] Tan [b] = 1 + (1-tan [a] Tan [b]) + Tan [a] Tan [b] = 2

What is the relationship between angles a and B when Tana * tanb = 1
RT

Tana * tanb = 1, that is, Tana and tanb are reciprocal, that is, Tana = ctanb, that is, Tana = Tan (90 degree-b), and a = 90 degree-b

Given that a and B are opposite numbers, C and D are reciprocal numbers, and the absolute value of X is 6, find the absolute value of X - (a + B + CD)

From the meaning of the title:
a+b=0
cd=1
The absolute value of x = 6
So:
simple form
=6-（0+1）
=6-1
=5

a. B is opposite to each other, C and D are reciprocal to each other, and the absolute value of X is 1

a. B is opposite to each other, a + B = 0
c. D is reciprocal, CD = 1
The absolute value of X is 1, x = 1 or - 1
x-(a+b+cd)x-cd=x-x-1=-1

It is known that a and B are opposite to each other, C and D are reciprocal to each other, and the absolute value of x = 2. Find the value of the second power of X - (a + B + CD) the 2003 power of X + (- CD)

It is known that a and B are opposite numbers, a + B = 0
c. D is reciprocal, CD = 1
The absolute value of x = 2. X = + 2 or - 2
The second power of X - (a + B + CD) the 2003 power of X + (a + b) + (- CD)
=4-(0+1)x+0+[-1]^2003
=4-x-1
=3-x
(1) X = 2, the above formula = 3-2 = 1
(2) X = - 2, the above formula = 3 + 2 = 5

Given that AB is opposite to each other and a is not equal to 0, CD is reciprocal to each other and the absolute value of M is 1, find the value of M-A / B + 2013 (a + b) / 2014 - CD

Because a and B are opposite numbers, and a is not equal to 0, so a / B is equal to - 1, a + B = 0, so 2013 (a + b) / 2014 = 0
So the formula can be simplified as M + 1-cd
And because CD is reciprocal to each other, CD = 1
So the original formula = m + 1-1 = M
The absolute value of M is 1, so the original formula is equal to plus or minus 1
Some symbols can't be typed, so they use Chinese characters~~