Mother bought 3 pots of roses and 2 pots of Mimosa, which cost 27 yuan in total. A pot of roses is 6.5 yuan more expensive than a pot of Mimosa. How much are each pot of roses and Mimosa?

Mother bought 3 pots of roses and 2 pots of Mimosa, which cost 27 yuan in total. A pot of roses is 6.5 yuan more expensive than a pot of Mimosa. How much are each pot of roses and Mimosa?

(27 + 6.5 × 2), = 40 △ 5, = 8 (yuan); 8-6.5 = 1.5 (yuan); a: the unit price of each pot of rose is 8 yuan, and that of a pot of Mimosa is 1.5 yuan

1+2/1+1+2+3/1+… 1+2+3+… 100 / 1 is equal to?

The format of the original question is wrong
1/（1+2）+1/（1+2+3）+...+1/(1+2+3+.+100)
=2/(2x3)+2/(3x4)+…… +2/(100x101)
=2x(1/2-1/3+1/3-1/4+…… +1/100-1/101)
=2x(1/2-1/101)
=1-2/101
=99/101

What is 1 + 1 + (1 / 1 + 2) + (1 / 1 + 2 + 3) + (1 / 1 + 2 + 3. + 100)

First of all, the denominator can be obtained by using the formula of summation of equal difference, which is (2 + n) * n / 2. Then each term is 2 / (1 + n) * n. this term can be written as 2 / N - 2 / (1 + n). If each term is separated, only the first term and the last term are left, and the result is 2-2 / 101 = 200 / 101
1+1/(1+2)+1/(1+2+3)+1/(1+2+3+4)+...+1/(1+2+3+...+100)
=2/(1*2)+2/(2*3)+2/(3*4)+2/(4*5)+...+2/(100*101)
=(2/1-1/2)+(2/2-2/3)+(2/3-2/4)+(2/4-2/5)+...+(2/100-2/101)
=2/1-2/101
=200/101
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perhaps
Let an = 1 / (1 + 2 +...) +n) , n is a positive integer
1 + 2 + +n=n*(n+1)/2
So, an = 1 / (1 + 2 +) +n)= 2/ n*(n+1)=2*（1/n－1/(n+1)）
therefore
1+1/(1+2)+ 1/(1+2+3) +… +1/(1+2+… +100)
= a1 +a2 +… +a100
=2*（1/1－1/(1+1)）+2*（1/2－1/(2+1)）+… +2*（1/100－1/(100+1)）
arrangement
=2*（1－1/2+1/2－1/3+… +1/100－1/101）
=2*（1－1/101）
=200/101