In the following two formulas, the same letter represents the same number, and different letters represent different numbers, then a + B + C + D + e + F + G=______ ．

In the following two formulas, the same letter represents the same number, and different letters represent different numbers, then a + B + C + D + e + F + G=______ ．

A + e = 7, so e = 7-a = 7-1 = 6; B + e = 0, we can know that B + e = 10 or B + e + 1 = 10, because C + F = 0, that is, C + F = 10, up to one, so B + e + 1 = 10, B = 10-1-e = 10-1-6 = 3; B + F = 8, f = 8

Here is an addition formula, in which different letters represent different numbers, d = 5. So, what's the answer to this formula?
DUNALD GERALD ＋________ RUBERT

D=5 =>T=0
Ten thousand bits: if the thousand bits have carry, then E = 9; if the thousand bits have no carry, then E = 0. Because t = 0, so e = 9
Ten bits: R is odd; 100000 bits: R > = 6. So r = 7 or 9. Because e = 9, so r = 7
100000 bits: g = 1
Thousand digits: because e is odd, the hundred digits have carry; so the hundred digits: l = 8; so the thousand digits: a = 4
Finally, only UNB and 236 are not sure. I'm too lazy to reason. I'll give you an exhaustive list: u = 2, n = 6, B = 3
5 2 6 4 8 5
1 9 7 4 8 5
7 2 3 9 7 0