Find LIM (x → 0) (√ (1 + x) - 1) / X limit process?

Find LIM (x → 0) (√ (1 + x) - 1) / X limit process?

LIM (√ 1 + x) - (√ 1-x) / X (x → 0) to find the limit, detailed steps, thank you!

According to the law of lobida, the derivative of molecule is 1 / 2 [1 / √ (1 + x) + √ (1-x)] = 1
So the limit is 1

LIM (x →∞) [(x ^ 3 + x ^ 2 + x ^ 1 + 1) ^ (1 / 3) - x] limit

=1/3
A = (x ^ 3 + x ^ 2 + x ^ 1 + 1) ^ (1 / 3) B = x first analyze the score and multiply it by (a ^ 2 + B ^ 2 + AB)
Then divide it by x ^ 2 at the same time, and for example, x ^ 2 / x ^ 3 = 0, the result is 1 / 3