Find the limit Lim x →∞ [(2x + 1) ^ 4 (x-1) ^ 6-5x (x ^ 8 + 8)] / (x + 2) ^ 10 =? Use Lim x →∞ [(2x + 1) ^ 4 (x-1) ^ 6-5x (x ^ 8 + 8)] / (x + 2) ^ 10 =? The simplest way to find How does the answer "original = LIM (2 ^ 4x ^ 4x ^ 6) / x ^ 10" come out? What is the principle?

Find the limit Lim x →∞ [(2x + 1) ^ 4 (x-1) ^ 6-5x (x ^ 8 + 8)] / (x + 2) ^ 10 =? Use Lim x →∞ [(2x + 1) ^ 4 (x-1) ^ 6-5x (x ^ 8 + 8)] / (x + 2) ^ 10 =? The simplest way to find How does the answer "original = LIM (2 ^ 4x ^ 4x ^ 6) / x ^ 10" come out? What is the principle?

The numerator and denominator are simultaneously divided by x ^ 10 to obtain:
The original formula = limx →∞ [(2 + 1 / x) ^ 4 * (1-1 / x) ^ 6-5 * (1 / x + 8 / x ^ 9)] / (1 + 2 / x) ^ 10,
=[(2+0)^4*(1-0)^6-5*(0+0)]/(1+0)^10,
=16.

Lim X in 2,2x ^ 2-5x + 2 / x ^ 2-x-2

Factorization of (2x-1) (X-2) / (X-2) (x + 1) up and down at the same time divided by X-2 to get 2x-1 / x + 1, 2 to get 1

Lim = (2x-3) / (x ^ 2-5x = 4) = how much is the limit! X -- 1

The numerator does not tend to zero, but the denominator tends to zero
So fractions tend to infinity
So there is no limit

What is 60 / 18.84?

84 = 18 and 21 / 25 = 471 / 25
60/18.84=60/（471/25）=60*（25/471）=1500/471=500/157