On the limit of higher numbers When x → 0, (1 + x ^ 2) ^ (1 / 3) - 1 is equivalent to (1 / 3) x ^ 2, that is, the limit of the first formula divided by the second formula when x → 0 is equal to 1. How can this be calculated? Please write down the calculation process. Thank you very much

On the limit of higher numbers When x → 0, (1 + x ^ 2) ^ (1 / 3) - 1 is equivalent to (1 / 3) x ^ 2, that is, the limit of the first formula divided by the second formula when x → 0 is equal to 1. How can this be calculated? Please write down the calculation process. Thank you very much

This formula can be used directly in the future
Your adoption is my driving force~

On the problem of the limit of higher numbers
When X - > 0, find the value of (1 / x) [(1 / x) - Cotx]

lim (1-xcotc)/x^2
=lim(tanx-x)/(x^2*tanx)
=lim(tanx-x)/x^3
=lim(sec^2x-1)/3x^2
=lim2sec^2xtanx/6x
=lim xsec^2x/3x
=1/3

The first proof of two important limits