If n is any integer, the value of (n + 11) 2-n2 can always be divided by K, then K is equal to () A. Multiple of 11b. 22c. 11 or 12D. 11

If n is any integer, the value of (n + 11) 2-n2 can always be divided by K, then K is equal to () A. Multiple of 11b. 22c. 11 or 12D. 11

∵ (n + 11) 2-n2, = (n + 11 + n) (n + 11-n), = 11 (2n + 11), ∵ (n + 11) 2-n2 can always be divided by 11

If n is any integer, the value of (n + 11) 2-n2 can always be divided by K, then K is equal to ()
A. Multiple of 11b. 22c. 11 or 12D. 11

∵ (n + 11) 2-n2, = (n + 11 + n) (n + 11-n), = 11 (2n + 11), ∵ (n + 11) 2-n2 can always be divided by 11

If the square difference of two consecutive odd numbers can always be divided by K, then K is equal to ()
A. Multiple of 4B. 8C. 4 or - 4D. 8

Let two consecutive odd numbers be 2n + 1, 2n + 3. According to the meaning of the question, we get that: (2n + 3) 2 - (2n + 1) 2 = (2n + 3 + 2n + 1) (2n + 3-2n-1) = 8 (n + 1), then the value of K is 8