Let {an} have 2n + 1 terms, the sum of all odd terms is 132, and the sum of all even terms is 129

The first term is A1, and the last term is a (2n + 1)
Odd terms have n + 1 terms, and s odd = (n + 1) [A1 + a (2n + 1)] / 2 = 132
Even number terms have n terms, and s even = n [A2 + a (2n)] / 2 = 129
Considering that a1 + a (2n + 1) = A2 + a (2n), the two equations are divided by each other
(n＋1)/n=132/129
The solution is n = 43

Let {an} have 2n + 1 terms, the sum of all odd terms is 132, and the sum of all even terms is 129

Let {an} have 2n + 1 terms, the sum of all odd terms is 132, and the sum of all even terms is 129

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