If a and B are natural numbers, and the square of a - the square of B = 63, how to find the value of a and B, The square of x-a-2x-2a = (x + a) ()

If a and B are natural numbers, and the square of a - the square of B = 63, how to find the value of a and B, The square of x-a-2x-2a = (x + a) ()

a^2-b^2=(a+b)(a-b)=63=7×3×3×1
Then:
When a + B = 9, A-B = 7, a = 8, B = 1
When a + B = 21, A-B = 3, a = 12, B = 9
When a + B = 63, A-B = 1, a = 32, B = 31

A number minus 100 is a square number, minus 63 is also a square number, how much is this?

The first square number is B2, the second square number is A2. From the meaning of the question, we can get: B2 + 100 = A2 + 63, A2-B2 = 100-63 = 37, that is: A2-B2 = 37 = 37 × 1. Considering the parity, we can see that a = 19, B = 18, this number is A2 + 63 = 19 × 19 + 63 = 424; a: this number is 424

A number minus 100 is a square number, minus 63 is also a square number, how much is this?

The first square number is B2, the second square number is A2. From the meaning of the question, we can get: B2 + 100 = A2 + 63, A2-B2 = 100-63 = 37, that is: A2-B2 = 37 = 37 × 1. Considering the parity, we can see that a = 19, B = 18, this number is A2 + 63 = 19 × 19 + 63 = 424; a: this number is 424