If the sum of binomial coefficients of each term in the expansion of (x Λ 2 - (1 / x)) Λn is 32, then the coefficient of the term containing x Λ 4 is

If the sum of binomial coefficients of each term in the expansion of (x Λ 2 - (1 / x)) Λn is 32, then the coefficient of the term containing x Λ 4 is

(1+1)^n=32
2^n=32
n=5
(x²-1/x)^5
C(5,a)(x²)^(5-a)(-1/x)^a
=C(5,a)(-1)^a (x)^(10-2a-a)
10-3a=4
a=2
therefore
Coefficient = C (5, a) (- 1) ^ a = C (5,2) (- 1) ^ 2 = 5 × 4 △ 2 = 10

In the expansion of binomial (x2-1 / x) n, if the sum of all binomial is 32, then the sum of coefficients in the expansion is 32

The sum of binomial coefficients refers to: cN 0 + CN 1 + CN 2 + +Cn, which is equal to 2 ^ n
2 ^ n = 32, n = 5
In the binomial, let x = 1, then, (1-1) ^ 5 = 0, and the sum of coefficients in the expansion is 0

It is known that in the expansion of (x-2y) ^ n, the sum of binomial coefficients of odd terms is 32. What is the largest term in the expansion?

∵ the sum of odd items is 32
∴（1/2）×2^n=32
n=6
The general term is t (R + 1) = C [6, R] x ^ (6-r) (- 2Y) ^ R = C6 (R) * - 2) ^ R * x ^ (6-r) y ^ R
If r = 4 is the largest term, then T5 = 240x ^ 2Y ^ 4

Find the binomial coefficient of the third term in the expansion of (x-2y) to the 7th power (expressed by C), and the coefficient of the third term is

T(r+1)=C(7,r)*x^(7-r)*(-2)^r*y^r
T(3)=C(7,2)*x^(7-2)*(-2)^2*y^2
The binomial coefficient of the third term is C (7,2)
The coefficient of the third term is C (7,2) * (- 2) ^ 2 * y ^ 2 = 84y & # 178;