Sum of coefficients in (2x-3y) ^ 9 expansion The sum of the absolute values of the coefficients is equal to

Sum of coefficients in (2x-3y) ^ 9 expansion The sum of the absolute values of the coefficients is equal to

(2x-3y)^9=a0x^9+a1x^8y+…… +a10y^9
Obviously A0, A2 And A10 is positive
a1,a3,…… And A9 is negative
So the sum of the absolute values of the coefficients is equal to = a0-a1 + A2-A3 + -a9+a10
Let x = 1, y = - 1
[2*1-3*(-1)]^9=a0-a1+a2-a3+…… -a9+a10=5^9
That is, the sum of the absolute values of the coefficients is equal to = a0-a1 + A2-A3 + -a9+a10=5^9
Let x = y = 1
(2*1-3*1)^9=a0+a1+a2+…… +a10=(-1)^9=-1
So the sum of the coefficients = - 1

After a prime number plus one, the sum is ()
A. Odd B. even C. odd or even D. cannot be discussed

From the analysis, we can see that: after a prime number plus 1, the sum is odd or even

Odd plus odd plus even equals prime, right?

Obviously wrong
Just give me an example to prove the contrary
3+5+2=10