If M and N are integers and (MX + a) (x-3a) = 3x ^ 2 + nax-3a ^ 2, find the value of M and n

If M and N are integers and (MX + a) (x-3a) = 3x ^ 2 + nax-3a ^ 2, find the value of M and n

Remove the bracket at the left end to get MX ^ 2 + (a -- 3mA) X -- 3A ^ 2 = 3x ^ 2 + NaX -- 3A ^ 2. According to the condition of polynomial equality, M = 3, a -- 3mA = Na, i.e. 1 -- 3M = n, so m = 3, n = -- 8

If (MX + 2) (X & # 178; - 3x + n) does not contain X & # 178; and X terms, find the value of M and n

(mx+2)(x²-3x+n)
=mx³+（2-3m）x²+（mn-6）x+2n
therefore
2-3m=0
m=2/3
mn-6=0
2/3n=6
n=9
In the top right corner of my answer, click comment, and then you can choose satisfied, the problem has been solved perfectly

Factoring factor 6a to the second power of (m-n) - to the third power of 8 (n-m)

The second power of 6A (m-n) - the third power of 8 (n-m)
=6a(m-n)²＋8(m－n)³
=2(m-n)²(3a＋4m－4n)