X + X to the negative first power = 4 find the square of X + X to the negative second power

X + X to the negative first power = 4 find the square of X + X to the negative second power

X + x ^ (- 1) = less than 4 square
x^2+2+x^(-2)=16
x^2+x(^-2)=16-2=14

Given x + 1 / x = 3, find the value of X-1 / x x x & sup2; + MX + n = (x-3) (x + 4), find (M + n) & sup

x^5+x^4+x^3+x^2+x+1
=x^2(x^3+1)+x(x^3+1)+(x^3+1)
=(x^3+1)(x^2+x+1)
=（x+1)(x^2+x+1)^2
x+1/x=3
Multiply both sides by X at the same time
x^2+1=3x
therefore
x^2-3x+1=0
(x+1)(x-4)=0
x1=-1 x2=4
Because X1 is a negative number, it can't be used as the denominator
Substituting x = 4 into X-1 / x = 11 / 3
Because x ^ 2 + MX + n = (x-3) (x + 4)
Merge the factors into (x-3) (x + 4) = x ^ 2 + X-12
That is, M = 1, n = - 12
So (M + n) ^ 2 = 121

The square of [1 and 3 / 5 * (1-4 / 9)] is equal to the square of [(1-1 / 6) * (- 2 / 5)]

The square of [1 and 3 / 5 * (1-4 / 9)] is equal to the square of [(1-1 / 6) * (- 2 / 5)]
=Square of [- 8 / 9] / square of [- 1 / 3]
=Square of [8 / 9 △ 1 / 3]
=Square of [8 / 3]
=64/9