Let three mutually unequal rational numbers be expressed in the form of 1, a + B, a respectively, and in the form of 0, a / B, B respectively Find 2010 power of a + 2009 power of B

Let three mutually unequal rational numbers be expressed in the form of 1, a + B, a respectively, and in the form of 0, a / B, B respectively Find 2010 power of a + 2009 power of B

Obviously a is not equal to 0
Otherwise, a / b = 0 and 0 are repeated
So a + B = 0
So a = - B, so a / b = - 1
So {1,0, a} = {0, - 1, B}
So B = 1, a = - 1
So a ^ 2010 = 1, B ^ 2009 = 1
So a ^ 2010 + B ^ 2009 = 2

Define a method to calculate acbd = ad BC and find the value of 1 / 2 of - 2 - 2

-2*2-（-1/2）*（2/5）
=-4+1/5
=-19/5

If a new operation is defined and the absolute value of ABCD = ad BC, then when the absolute value of 2x4x = 27, x =?
The absolute value of ABCD | ab | upper and lower two connected, the absolute value of 2x4x | 2 4 | upper and lower two connected
|cd| |x x| |

|a b|
|c d| = ad - bc
|2 4|
|x x| = 2x - 4x =27 ∴ x = -13.5
Note: This is the simplest determinant calculation!