Given that the monomial (m-2) x3yn-3 is a quintic monomial with respect to the letters X and y, what are the conditions for M and N?

Given that the monomial (m-2) x3yn-3 is a quintic monomial with respect to the letters X and y, what are the conditions for M and N?

According to the meaning of the problem, 3 + (n-3) = 5, and m-2 ≠ 0, the solution is n = 5, and m ≠ 2

It is known that the monomial (| m | - 2) * x ^ 3 * y ^ (n-2) is a quintic monomial with respect to the letters X and Y. find the size of M and n

Because (| m | - 2) * x ^ 3 * y ^ (n-2) is a monomial, so (| m | - 2) is not equal to 0, so | m | - 2 is not equal to 2, that is, M is not equal to 2 or - 2
Because it is a quintic monomial, n-2 equals 5-3 = 2, that is, n = 4
So m is not equal to 2 or - 2, n = 4
LZ, I learned it last year. I'm forgetting it this year. If I mean, if it's wrong Don't blame me. By the way, remember to add some points

When X-Y / x + y is equal to 1 / 2, find Y-X / x + y minus 2x + 2Y / X-Y

x-y/x+y=1/2
Let x = 3, y = 1
Substituting it, we can get: (Y-X / x + y) - (2x + 2Y / X-Y) = - 4 (1 / 2)