Write all numbers with the same quotient and remainder (not 0) as 8

Write all numbers with the same quotient and remainder (not 0) as 8


Let quotient and remainder be m, then x = 8m + M = 9m
That is, all numbers are multiples of 9, 9, 18, 27



What is the number of 2 divided by 6 so that there is no remainder at the end of the quotient


The number of divisor is 2, right
If there is a zero at the end of the quotient, then the divisor should also have a zero
According to the question you give, there is no answer
You are looking at the title carefully. Is it wrong



How many kilometers is a light year? Thank you, Dashen


A light year is about 9460 billion km



The PI is round______ And its______ The ratio of the two


From the meaning of PI, we can know that: Pi is the ratio of the circumference of a circle to its diameter, and the value of PI is π; so the answer is: circumference, diameter



Find the area of the spherical surface: x ^ 2 + y ^ 2 + Z ^ 2 = a ^ 2 contained in the cylindrical surface x ^ 2 + y ^ 2 = ax
If the shadow Y > 0, x ^ 2 + y ^ 2 = ax, then the area a = 4A ∫ D θ∫ [1 / [(a ^ 2-r ^ 2)] ^ 1 / 2DR, where (θ is 0 to π / 2, R is 0 to ACOS θ), why take it as the whole x ^ 2 + y ^ 2 = ax of its projection on the xoy plane, and its area a = 2A ∫ D θ∫ [1 / [(a ^ 2-r ^ 2)] ^ 1 / 2DR, where (θ is - π / 2 to π / 2, R is 0 to ACOs θ), is the answer different? Is that wrong?


The area area of a = 4A ∫ D ∫ D ∫ [1 / [(a ^ 2-r ^ 2-r ^ 2)] ^ 1 / 2DR, in which (θ value is 0 to π / 2, and R value is 0 to ACOS θ) should be a = 4A ∫ D ∫ [1 / [(a ^ 2-r ^ 2-r ^ 2-r ^ 2)] ^ 1 / 2 * RDR, in which (θ value is 0 to π / 2, and R value is 0 to ACOS [1 / [(a ^ 2-r ^ 2-r ^ 2-r ^ 2-r ^ 2-r ^ 2-π / 2 to π / 2, and the R value is 0 to ACOS θ, the ACOS is also a = 2A 87474747/ [(a ^ 2-r ^ 2)] ^ 1 / 2rdr
The mistake you made is that DXDY = rdrd, θ, R must not be omitted when it is converted to polar coordinates



Is the derivative to the - x power of a equal to the - x power of a * LNA? How? I only know that the derivative to the x power of a = the x power of a * LNA


Well, you don't need to master the derivation process in high school
The formula is given directly in the book. Just remember it
By the way, the general formula is only a separate test, beginners really do in the future is not used
Take e ^ x derivative = e ^ xlne = e ^ x as the main!



If a is an integer, then the cube-a of a can be divided by 6, right


a^3-a=a(a^2-1)=a(a+1)(a-1)
It is easy to prove that at least one of them is a multiple of 3 and one is a multiple of 2
So the proposition is true



Let the equation of ellipse x2 / 16 + Y2 / 12 = 1, then the eccentricity of the ellipse is


Process x ^ 2 / 16 + y ^ 2 / 12 = 1
a²=16,a=4
b²=12
c²=a²-b²=16-12=4,c=2
Eccentricity e = C / a = 2 / 4 = 1 / 2
Hope to help you



I'll write some numbers for you: 14, 20, 24, 28, 40, 18. Can you express them in the form of the sum of two prime numbers?


14=11+3
20=17+3
24=11+13
28=11+17
40=37+3



The solution of inequality about X: loga (x ^ 2 + X-2) > loga (x + 1-2 / a) + 1
Please read the question before answering. My teacher didn't agree with the answer... Please, everyone!


Log a (x ^ 2 + X-2) > log a (x + 1-2 / a) + 1 = log a (AX + A-2) (a cannot be equal to 0) suppose a > 1, then x ^ 2 + X-2 > ax + a-2x ^ 2 + X-2 > 0 ① ax + A-2 > 0 ② x ^ 2 + (A-1) x-a > 0 ③ the solution is (x + a) (x-1) > 0, so x > 1 or x0, so x > 1 or X (2-A) / a = 2 / A-1