In the calculation of a problem, the divisor 65 is regarded as 56. The result shows that the quotient is 13 and the remainder is 52. What is the correct quotient?

In the calculation of a problem, the divisor 65 is regarded as 56. The result shows that the quotient is 13 and the remainder is 52. What is the correct quotient?


56 × 13 + 52 = 728 + 52 = 780780 780 △ 65 = 12; a: the correct quotient is 12



The first three numbers in a column are 1, 7 and 8 in turn, and each of them is the remainder obtained by dividing the sum of the three adjacent numbers in front of it by 4, then the sum of the first 2011 numbers in this column is______ .


This sequence: 1, 7, 8, 0, 3, 3, 2, 0, 1, 3, 0, 0, 3, 3, 2, 0, 1, 3, 0, 0, 0 (2011-3) △ 8 = 251 (0 + 3 + 3 + 2 + 0 + 1 + 3 + 0) × 251 + 1 + 7 + 8 = 12 × 251 + 16 = 3028, so the answer is: 3028



Mathematics, thank you! A column of numbers, the first three are 1,9,9, after each is the sum of the three adjacent numbers in front of it divided by the remainder of 3, find this column of numbers
What is the number of 2008 in


The column numbers are: 1, 9, 9, (1, 1, 2, 1, 1, 0, 2, 0, 2, 1, 0, 0), (1, 1, 2, 1, 1, 1, 0, 2, 0, 0, 2), (1, 1, 2
It can be seen that starting from the fourth number, 13 numbers are in a cycle
(2008-3) △ 13 = 154. Remaining 3
So the number 2008 is 2



The waist length of an isosceles right triangle is 4.5cm, and its area is ()


The waist length of an isosceles right triangle is 4.5cm, and its area is [(1 / 2) × (4.5) × (4.5) = 10.125cm & # 178;]



In a right triangle, the angle ABO is 90 degrees, the point B is on the X axis, the point a is the intersection of the straight line y = x + m and the hyperbola y = m / X in the first quadrant, and the triangle area AOB=
Finding the value of M
AOB=6


Triangle area AOB =?
-------------------------The title is incomplete
-----------------------------------------
Let a (x, y)
Then y = m / X
Triangle AOB area = AB * Bo / 2 = XY / 2 = m / 2
The area of triangle AOB = 6
So, M / 2 = 6
m=12



The first derivative of Ln (SiNx)


(ln(sinx))'=(sinx)'/(sinx)=cotx
Adopt



Write the words as they are


Slowly, quickly Warm, rustling AI 1ai1 adj. Pain. AA slowly ban7ban7 adj. Slowly. AA slightly bi5bi5 adj. Slightly; soft and small. AA depressed bun7bun7 adj. Depressed mood. AA early ca2ca2 adj



Given the image of quadratic function y = ax ^ 2 + BX + C, given a (negative) and C (positive), how to judge the positive and negative of B?


According to the axis of symmetry x = - B / 2A
If the symmetry axis is on the right side of the Y axis, then the symmetry axis X = - B / 2A > 0, and a is negative, then B must be positive
If the axis of symmetry is on the left side of the y-axis, then the axis of symmetry x = - B / 2A



What are the minimum and maximum values of the square + 2x-3 (- 2 ≤ x ≤ 2) of the function y = x
What are the minimum and maximum values of the square + 2x-3 (- 2 ≤ x ≤ 2) of the function y = x
What are the minimum and maximum values of the function y = - 1 / 2 x square + X + 1 / 2 (- 3 ≤ x ≤ - 1)


(1) Maximum: 5, minimum: - 3
(2) Maximum: - 1, minimum: - 7
I am also junior three, just finished a function, this kind of problem is to set the minimum number in the X range is the minimum value, the maximum number in the range is the maximum value~



(a-b) (a + b) 3-2ab (A2-B2), how to simplify