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Current calculation of three phase electricity According to the formula P = 1.73ui Then the three-phase current is 98.110.105 respectively. How to calculate the power In addition, there is a 400v30kw51.4a generator. Does 51.4a mean that each phase can carry 51.4a current
When the power factor cos φ = 1:
P＝1.732UI＝1.732×0.38×(98＋110＋105)/3≈69(KW)
Or:
P＝98×0.22＋110×0.22＋105×0.22≈69(KW)
The rated current indicated on the nameplate is 51.4a, which means the safe current carrying capacity of each phase is 51.4a
Accurate calculation method of three phase power
For advice:
It is known that the three-phase electricity is 380V (three-phase four wire). The actual current of the three live wires measured are 6.69a, 5.89a and 5.54a respectively. Please tell us the accurate calculation formula and settlement results. I found a lot of information on the Internet, but the more I read it, the more confused I am. How much is the total power of the three-phase electricity?
3.2Kw, a: 1.18kw & nbsp; & nbsp; B: 1.04kw & nbsp; & nbsp; C: 0.98kw & nbsp; & nbsp; & nbsp; power factor: 0.8, the current of each phase is different, then only p = uicos can be used, and the total power is the sum of three phases
How to calculate the power of three-phase electricity?
Total power of three-phase electricity: P = √ 3 * u * I * cosa, u is line voltage, I is line current, cosa is power factor, when it is pure resistance load, cosa = 1
Help me to clarify the calculation of three-phase electric power,
Three phase total power s = root 3 * line voltage U * line current I = 3 * phase voltage U1 * phase current I1 star (y) connection method: line voltage U = root 3 * phase voltage U1 line current I = phase current I1 triangle (d) connection method: line voltage U = phase voltage U1
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