When a resistor is connected to a circuit, the consumed power is 110W. When 3C charge is passed, 330j of electric energy is converted into internal energy, then () A. The voltage applied to the resistor is 330vb. The current through the resistor is 1Ac. The power on time of the resistor is 3SD. The resistance value of the resistor is 110 Ω

When a resistor is connected to a circuit, the consumed power is 110W. When 3C charge is passed, 330j of electric energy is converted into internal energy, then () A. The voltage applied to the resistor is 330vb. The current through the resistor is 1Ac. The power on time of the resistor is 3SD. The resistance value of the resistor is 110 Ω


A. According to w = Qu, there are: u = WQ = 330j3c = 110V, so a is wrong; B, according to P = UI, current: I = Pu = 110w110v = 1a, so B is correct; C, according to q = it, time: T = Qi = 3c1a = 3S, so C is correct; D, according to ohmic law, electric



When a fluorescent lamp is connected to the lighting circuit and works normally, its current is 0.13a. If it is powered on for 10min, there will be a problem______ J's electricity is converted into heat and energy______ Yes


Through the filament current I = 0.13a, lighting circuit voltage U = 220V, power on time t = 10min = 600s, according to the formula w = Pt. P = UI, we can deduce w = uit. Substituting the above figures, we can get w = 220V × 0.13a × 600s = 17160j. Then 17160j of electric energy is converted into heat energy and light energy



How to calculate the voltage, current, power and resistance
For example, how much current is 200V 60W, and how much current is 50V 60W


Voltage x current = power
Voltage △ resistance = current
Current x resistance = voltage
60W △ 220V = 0.272a ----- 60W / 220V bulb current 0.272a
60W △ 50V = 1.2A -------- 60W / 50V bulb current 1.2A



Power calculation of resistance hybrid circuit
When doing a certain experiment, we need a 500 ohm, 1 watt resistance element, but now there are only 1 / 4 watt 250 ohm, 1K ohm, 2K ohm resistance elements. How to solve this problem?
Is this the only one on the first floor?
It seems that this is the only one, and none of the others is good


There are not so many ways to solve this problem. Although the method of the first floor is right, it is not only to meet the problem of power and resistance. R = 500 Ω, R1 = 250 Ω, R2 = 1000 Ω, R3 = 2000 Ω. Through calculation, we can get the following corresponding relationship R R1 R2 r3i √ 2I / 2 √ 2I / 4 I / 4U 2 √ 2U √ 2U on u