The calculation of the voltage in the circuit with resistor diodes and light emitting diodes in series In 12V DC power supply circuit, 1K resistor, diode 4007 and a LED are connected in series, how much is the circuit current, how much is the voltage at both ends of the diode and the LED, and how much is the voltage at both ends of the LED Is the voltage drop of the diode the terminal voltage at both ends of the diode?

The calculation of the voltage in the circuit with resistor diodes and light emitting diodes in series In 12V DC power supply circuit, 1K resistor, diode 4007 and a LED are connected in series, how much is the circuit current, how much is the voltage at both ends of the diode and the LED, and how much is the voltage at both ends of the LED Is the voltage drop of the diode the terminal voltage at both ends of the diode?


The voltage at both ends of LED is about 1.8V for red, 2V for green and 0.7V for common diode. Subtract the voltage of these two diodes from 12V and divide it by 1K resistance = the current of the circuit



I would like to ask 20, 18, 15, 12, 9 and 5 LED lamps in series, 5V voltage; how much resistance do they add?
It is used in the control of single chip microcomputer
I want to use SCM control, this is 5V voltage ah, ready to make a water lamp


If the voltage is 5V in series, it can't be done in parallel. Even for ordinary light-emitting diodes, the conduction voltage should be 2V, one in series plus 2V, and 20 in series. You can calculate the voltage by yourself. Parallel connection is feasible, but the power supply should have enough power to drive the current of the maximum 20 LED lights. According to the calculation of ordinary 20mA white LED, the conduction voltage is 3V, the current is 10mA, 5 LEDs, and the current limiting resistance is (5-3) / (5 * 10) = 40, According to this formula, calculate the number of current limiting resistors to be added, and take the standard value