The voltage at both ends of the small bulb is 3.8V, and the current passing through is 0.3A. Within 10min, the current does work on -- J and consumes -- J's electric energy To get the formula, the process
Power: P = UI = 3.8 * 0.3 = 1.14w
W=P*t=1.14*10*60=684J
Current work = consumed energy = 684j
If the voltage at both ends of a bulb is 220 V and the maximum energy consumed within 10 min is 2.4 * 10000 J, what is the power? Current? Resistance?
P=W/t=24000/(10*60)=40W
I=P/U=40W/220V=0.18A
R = u ^ 2 / P = 220 * 220 / 40 = 1210 Ω (or r = u / I = 220 / 0.18 = 1222 Ω, the difference is because the current of the latter is about equal to, so there is error)
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