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The distance between a and B is 180 km, and it takes 3.6 hours for a motorcycle to complete the whole journey. The speed ratio of a car to this motorcycle is 4:5. If the two cars leave from a and B at the same time, how many hours will they meet on the way?
① The speed of motorcycle per hour is: 180 △ 3.6 = 50 (km); ② the speed of car per hour is: 50 × 45 = 40 (km); ③ the distance between a and B is: 180 △ 50 + 40, = 180 △ 90, = 2 (H). Answer: the two cars meet on the way after 2 hours
The distance between a and B is 40 km, the speed of motorcycle is 45 km / h, and the speed of freight car is 35 km / h
(1) When will the two cars meet each other? Let two cars meet in X hours, then there is 45x + 35x = 40, and the solution is: x = 0.5, two cars meet in 0.5 hours; (2) let two cars start at the same time and travel in the same direction, and the motorcycle arrives x hours earlier than the freight car? Then there is 4045 + x = 4035, and the solution is x = 1663
A. The distance between B and B is 120 kilometers. It is known that the walking speed of people is 5 kilometers per hour, and that of motorcycles is 50 kilometers per hour. The back seat of motorcycles can take one person. Q: how many hours does it take at least to get from a to B with three people and a motorcycle? (reserved - small emblem)
Let a ride motorcycle with B from a to D for X kilometers, put down B and ride motorcycle back. At this time, C has walked from a to e and met a at F. a rides motorcycle with C straight to B, just at the same time with B. 2 × [(x-x50 × 5) / (50 + 5)] + (120-x) / (50 = (120-x) / (5 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 2×[910x÷55]+2.4-x50=24-x5 9275x+2.4-x50=24-x5 18x+1320-11x=13200-110x 7x+110x=13200-1320 117x=11880 &Answer: it takes at least 5.7 hours from a to B
The speed of the motorcycle is 48 kilometers per hour and the speed of the bicycle is 48 kilometers per hour
The speed is 16 kilometers per hour. The motorcycle breaks down on the way. After one hour's repair, it goes on. When the two cars meet, the bicycle runs for () hours
Suppose that when two cars meet, the bicycle runs for t hours, and the motorcycle runs for T-1 hours
48*（t-1）+16t=208
T = 4 hours
The distance between a and B is 40 km, the speed of motorcycle is 45 km / h, and the speed of freight car is 35 km / h
(1) When will the two cars meet each other? Let two cars meet in X hours, then there is 45x + 35x = 40, and the solution is: x = 0.5, two cars meet in 0.5 hours; (2) let two cars start at the same time and travel in the same direction, and the motorcycle arrives x hours earlier than the freight car? Then there is 4045 + x = 4035, and the solution is x = 1663
The distance between a and B is 40 km, the speed of motorcycle is 45 km, and the speed of truck is 35 km per hour (1)
(1) (2) if two vehicles start from place a at the same time, when the motorcycle arrives at place B, how many kilometers are there from place B?
One and a half hours
20 km
The distance between city a and city B is 600 km. The freight cars drive from city a to city B at the speed of 40 km per hour. Five hours later, the passenger cars drive to city a, and the two cars meet again after four hours
The bus travels thousands of meters per hour? After meeting, the two cars continue to drive separately. Which car reaches the terminal first?
Let's set the equation
The bus is set to travel x kilometers per hour
40 times (5 + 4) + x times 4 = 600
The solution is x = 60 (km / h)
Continue:
The truck is 600-40 times 9 = 240 km from Yicheng
Arrival time of truck in city B: 240 divided by 40 = 6 hours
The distance between the bus and Jiacheng is 600-240 km = 360 km
Bus arrival time: 360 divided by 60 = 6 hours
So the two cars arrived at the same time
The distance between station a and station B is 350 kilometers. A truck starts from station a at a speed of 50 kilometers per hour. After driving for 1.2 hours, a bus leaves from station B
A and B are 350 kilometers apart. A truck starts from a station at a speed of 50 kilometers per hour. After driving for 1.2 hours, a bus starts from B station and meets after 2.5 hours. What is the speed of the bus?
A 1.2-hour driving distance: 50 × 1.2 = 60 km
1.2 hours after departure, the distance between the two vehicles: 350-60 = 290km
When the two vehicles meet in 2.5 hours, the sum of the two vehicles' speed per hour is 290 △ 2.5 = 116 km / h
Bus speed: 116-50 = 66 km / h
Integral: (350-50 × 1.2) △ 2.5-50 = 66 km / h
A: the speed of the bus is 66 km / h
The distance between a and B is 468 km. A bus and a freight car leave from a and B at the same time. They meet three hours later. The speed of the bus is the same as that of the freight car
6 / 7, the speed of the bus
Let the freight car speed be X
（X+6/7X）3=468
13/7X*3=468
13/7X=156
X=84
6/7X=84*6/7=72
The distance between station a and station B is 168 km. The speed of a freight train from station a is 36 km / h, and that of a passenger train from station B is 48 km / h
I'm sorry. I added: after the truck left for an hour, the two cars moved forward at the same time. After a few hours, the two cars met.
168-36 = 132 (km)
132 ÷ (36 + 48) = 11 / 7 (hours)
11 / 7 + 1 = 18 / 7 (hours)
A: Yes
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