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On a map with a scale of 1:6000000, the distance between a and B is 25cm. A plane flies from a to B at 8:30 a.m. and arrives at 9:45 a.m?
Time = 1 hour, 15 minutes = 1.25 hours
Distance = 25 × 6000000 △ 100000 = 1500 km
therefore
Average speed = 1500 △ 1.25 = 1200 km / h
On the map with a scale of 1 / 6000000, the distance between a and B is 25 cm. At 11:30 at noon, a plane flies from a to B, and arrives at 1:00 in the afternoon. How many kilometers does this plane fly per hour?
Actual distance = 25 * 6000000 = 150000000cm = 150km
The duration is 1.5 hours
Speed = 150 / 1.5 = 100 km / h
The distance between a and B is 480km. A local train runs 60km per hour from a and an express train 65km per hour from B
1. If two cars leave at the same time and meet at x time, the equation is
2. After X hours, the distance between the two vehicles is 620 km. The equation is
3. When the slow train starts for 1 hour, the two trains are facing each other. After the slow train starts for X hours, the distance between the two trains is 100 km. The equation is as follows
1.x*(60+65)=480
2.x*(60+65)=620-480
3.x*60+65*(x-1)=480-100
The distance between a and B is 480 km. A local train departs from a and an express train departs from B at a speed of 60 km per hour. If the local train departs for 1 hour first, the local train departs from B at a speed of 65 km per hour
If the slow train starts at 1H and runs in opposite directions, and the fast train starts at XH and then meets, the equation is given based on this condition
The express will meet in X hours
60*1+（60+65）x=480
60+125x=480
125x=420
x=3.36
A: the express will meet after 3.36 hours
The express train from a to B is 6 hours and the local train is 8 hours. The two trains leave at the same time. When they meet, the express train runs 60km more than the local train. How many kilometers are there between a and B?
420Km
A. B is 480km away from the two places. A local train runs 60km an hour from a, and an express train runs 65km an hour from B. answer the following questions:
1. If the slow train leaves for one hour first, the two trains are facing each other, and the fast train meets after XH, the equation ()
2. If the two vehicles leave at the same time and travel in opposite directions, the distance between the two vehicles is 620km after XH, then the equation ()
3. If two trains leave at the same time and go in opposite directions, the express train will be behind the local train, and the express train will catch up with the local train after XH, then the equation ()
1、480=(60+65)*x+60
2、480+(60+65)*x=620
3、(65-60)*x=480
An express train runs 65km per hour from station a to station B, and an idle train runs 60km per hour from station B at the same time. When it meets, the express train runs 20km more than the idle train
An express train goes from station a to station B at 65km per hour, and a local train goes from station B to station B at the same time at 60km per hour. When it meets, the express train goes 20km more than the local train. How many km is the distance between station a and station B?
Meeting time:
20 ÷ (65-60) = 4 (hours)
Distance between station a and station B:
(65 + 60) × 4 = 500 (km)
The passenger and freight cars set out from both places at the same time and run in opposite directions. After 4.5 hours, they meet. The passenger car runs 56km per hour and the freight car 60km per hour
How many kilometers are there between a and B
Distance between a and B: (56 + 60) × 4.5 = 522km
A passenger car and a freight car start from a and B which are 72km apart at the same time. They run in opposite directions and meet at two-thirds of the time. The passenger car runs 60km per hour and the freight car runs 60km per hour
Write the reason step by step
Speed sum of two vehicles: 72 △ 2 / 3 = 108 km / h
Speed of truck: 108-60 = 48 km / h
Party A and Party B are facing each other from the two places of AB, with a distance of 60km / h and B distance of 100km / h. Party A starts 15 minutes earlier than Party B, and when they meet, Party A walks 65km less than Party B, so as to find the distance between Party A and B
Let B walk for X minutes when they meet. A's speed is 216 meters per second. B's speed is 360 meters per second
The distance a takes + the distance b takes = the distance between ab. the equation can be solved
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