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A and B ride from A. B. It is known that the speed of a and B is faster than 2:3. A starts 15 minutes earlier than B. after 1 hour and 45 minutes, a meets B. at this time, a walks 6 kilometers less than B. how about the speed of a and B and the distance between a and B?
Suppose the speed of a is 2a and that of B is 3a. A is 15 minutes earlier than B, and the total time is 1 hour and 45 minutes, so they spend 90 minutes on the road together
A walks 6 kilometers less than B, that is, 105 * 2A = 90 * 3a-6, and a = 0.1
The speed is 0.2, 0.3 km / min
The distance between the two places is 0.5 * 90 = 45 km
It is known that the speed ratio of a and B is 2:3. A starts 15 minutes earlier than B and passes through 1 hour and 30 minutes
At this time, a walks 6 kilometers less than B. find the speed of a and B, the distance between a and B. 0-0 / / / fast!
Suppose the speed of a is 2x km / h, then the speed of B is 3x km / h
2x×(15/60+1.5）+6=3x×1.5
2x×1.75+6=4.5x
x=6
That is: the speed of a is 2 × 6 = 12 (km / h), and the speed of B is 3 × 6 = 18 (km / h)
Party A and Party B start from place a to place B, and Party A walks while Party B rides. If Party A starts 6km first and then Party B starts, Party B will arrive at place B at the same time with Party A after walking for 45 minutes. If Party A starts for one hour, Party B can catch up with Party A in half an hour to find the distance between a and B
Using binary linear equation
Let a be XKM / h and B be y
6+3/4X=3/4Y
x+1/2x=1/2y
The solution is x = 4, y = 12,
AB distance = 3 / 4Y = 9 km
A and B ride bicycles from a and B to each other at the same time. For the first time, they meet at a distance of 7 km from B. after meeting, they continue to drive, and then stand back at their destination. They meet again at a distance of 4 km from A. how many kilometers is the distance between a and B?
According to the meaning and analysis of the question, we can get: 7 × 3-4, = 21-4, = 17 km
A and B set out from a and rode to B at the same time
It is known that the distance between a and B is 30 km. A walks 3 km more per hour than B, and 40 minutes earlier than B. suppose B walks x km per hour, then the equation is ()
A.30/x-30/(x-3)=2/3
B.30/x-30/(x+3)=2/3
C.30/(x+3)-30/x=2/3
D.30/(x-3)-30/x=2/3
Choose B
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