Party A and Party B start from A. B at the same time, and Party A rides a bicycle Party A and Party B set out from A.B. at the same time. Party A rode a bicycle and Party B rode a motorcycle. They drove at a constant speed along the same route. After three hours of departure, they met. It is known that Party B traveled 90 meters more than party a when they met again. After one hour of meeting, Party B arrived at place A. they asked what the speed of Party A and Party B was and how to solve the equation

Party A and Party B start from A. B at the same time, and Party A rides a bicycle Party A and Party B set out from A.B. at the same time. Party A rode a bicycle and Party B rode a motorcycle. They drove at a constant speed along the same route. After three hours of departure, they met. It is known that Party B traveled 90 meters more than party a when they met again. After one hour of meeting, Party B arrived at place A. they asked what the speed of Party A and Party B was and how to solve the equation

Let X be the velocity of a and y be the velocity of B
After three hours of meeting, it is known that B traveled 90 kilometers more than a
∴3（y-x）=90
After meeting, B arrived at a place in an hour
It shows that the distance b takes one hour is the same as that a takes three hours
y*1=x*3
∴x=15
y=45

a. The distance between B and B is 60 kilometers. A and B start from a and B by bike and travel in opposite directions. A starts 20 minutes later than B and drives 3 times more per hour than B
One hour and 40 minutes after a set out, they met and asked a and B how many kilometers each hour?

20 minutes = 1 / 3 hour
1 hour 40 minutes = 5 / 3 hours
If a is x kilometers per hour, B is x-3 kilometers
5/3x+(1/3+5/3)x(x-3)=60
5/3x+2x-6=60
11/3x=60+6
11/3x=66
x=18
B 18-3 per hour = 15 km
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The distance between a and B is 60 kilometers. A and B ride bicycles from a and B. If a starts half an hour earlier than B, B travels 2 kilometers more every hour than a,
The distance between a and B is 60 kilometers. A and B ride bicycles from a and B. If a starts half an hour earlier than B, and B travels 2 kilometers more than a per hour, then the distance they travel is exactly the same.

Let a's speed be x km / h. After t hours, two people meet
[t+(30/60)]x=(x+2)t
[t+(30/60)]x+(x+2)t=60
2tx+x=2xt+4t
x=4t
2*(x+2)t=60
xt+2t=30
4t^2+2t=30
2^+t-15=0
(t+3)(2t-5)=0
t=5/2
X = 4 * (5 / 2) = 10 km / h
B = 10 + 2 = 12 km / h
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The distance between a and B is 60 kilometers. A and B start from ab by bike and travel in opposite directions. A starts 20 minutes later than B, every hour
A. B is 60 kilometers away from each other. A and B start from ab by bike and travel in opposite directions. A starts 20 minutes later than B and travels 3 kilometers more per hour than B. they meet each other 1 hour and 40 minutes after a starts. What's the speed of a and B

Suppose B's speed is x km / h, then a's speed is (x + 3) km / h
5 / 3 (x + 3) + 2x = 60, the solution is x = 15
So the speed of B is 15 km / h and that of a is 18 km / h