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The speed of a is 12 kilometers per hour, the speed of B is 15 kilometers per hour, and the speed of a is middle
A broke down for 30 minutes, so it took two hours
2 * 12 = 24 km, so a line of 24 km
It's 2.5 hours from 8:00 to 10:30, so B has 2.5 hours
2.5 * 15 = 37.5km, so B traveled 37.5km
24 + 37.5 = 61.5km
So AB is 61.5km apart
A starts from place a at a speed of 12 kilometers per hour. 15 minutes later, B starts from place B at a speed of 14 kilometers per hour. When they meet, a is 1.5 kilometers away from the center of AB, so find the distance between ab
fast
Let B travel x hours to meet, then a time is x + 0.25. Let the total distance be y. (15 minutes = 0.25 hours). According to the meaning of the question, we can get: a travel distance is 12 * (x + 0.25); B travel distance is 14x, so y = 12 * (x + 0.25) + 14x, and because a has exceeded the midpoint of 1 km when two people meet, we can get: Y /
From a and B, they start at 8 o'clock, 36 kilometers away at 10 o'clock, and 36 kilometers away at 12 o'clock
First order equation with one variable
The first time when they were 36 kilometers apart, they did not meet. The second time when they were 36 kilometers apart, they met and continued to ride
Let the distance between AB and ab be x km
(X-36)/(10-8)=(X+36)/(12-8)
(X-36)/2=(X+36)/4
2(X-36)=X+36
2X-72=X+36
X=108
The distance between a and B is 108 km
Two hours later, they are 36 kilometers apart. Two hours later, they are still 36 kilometers apart. What is the distance between a and B?
Speed of two persons = (36 + 36) △ 2 = 36 km / h
Encounter time = 2 + 2 / 2 = 3 hours
Distance between the two places = 3 * 36 = 108 km
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