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The distance between a and B is 60 kilometers. A and B ride bicycles from a and B to each other. If a starts half an hour earlier than B, B travels 2000 more per hour than a M. then when they meet, the distance they travel is exactly the same. Find the speed of a and B. don't use fractions, just make a binary linear equation system
Let a speed x, then B speed x + 2
Let a use y, then B use y-0.5
The distance is equal. It's 30
Lie equation
x*y=30
(x+2)(y-0.5)=30
The solution is x = 10, y = 3
A speed 10, B speed 12
It is known that the speed ratio of a and B is 2:3. A starts 15 minutes earlier than B, and a starts 105 minutes
It is known that the speed ratio of a and B is 2:3. A starts 15 minutes earlier than B. after 105 minutes, a meets B. at this time, a walks 12 kilometers less than B. find out the car speed of a and B and the distance between a and B!
The key is the second question,
Just write the distance formula of AB, why do I calculate 84?
Set a to drive x kilometers per minute
Then B is 3 / 2x
（105-15）3/2x - 105x=12
x=0.4
Then the velocity of B is 0.4 * 3 / 2 = 0.6 m / min
A. B distance between two places = (105-15) * 0.6 + 105 * 0.4 = 96km
It is known that the speed ratio of a and B is 2:3, and a starts 15 minutes earlier than B, after one hour
When we meet B in 45 minutes, a walks 6 kilometers less than B, asking for A. B's speed and the distance between a and B
One hour 45 minutes = 1.75 hours. The common time of Party A and Party B is: one hour 45 minutes-15 minutes = one hour 30 minutes = 1.5 hours. If the speed of Party B is x kilometers per hour, then the speed of Party A is 2 / 3x kilometers. The equation is: 1.5x-2 / 3x × 1.75 = 61.5x-7 / 6x = 61 / 3x = 6x = 18. The speed of Party B is: 2 / 3x = 2 / 3 × 18 = 12a, B
It is known that the speed ratio of a and B is 2:3. A starts 15 minutes earlier than B. after 1 hour and 45 minutes, a meets B. at this time, a walks 6 kilometers less than B. how much speed do a and B ride? (2) What is the distance between a and B?
(1) One hour 45 minutes = 14560 hours = 1.75 hours; 15 minutes = 0.25 hours; 1.75 hours - 0.25 hours = 1.5 hours; suppose that the speed of a is 2x km / h, and that of B is 3x km / h. 1.75 × 2x + 6 = 1.5 × 3x, & nbsp; & nbsp; & nbsp; & nbsp; 3.5x + 6 = 4.5X, & nbsp; & nbsp; & nbsp; & nbsp
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