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A and B leave from a and B at the same time and meet each other in two hours. After meeting, the two vehicles continue to move forward. When a arrives at B, B is 60 kilometers away from A. the speed ratio of the two vehicles is known to be 3:2?
If the whole process is regarded as unit "1", then the distance between a and B is 60 (1-12 × 43) = 60 / 13, = 180 (km). The speed sum of a and B is 180 / 2 = 90 (km)
A and B leave from a and B at the same time and meet each other in two hours. After meeting, the two vehicles continue to move forward. When a arrives at B, B is 60 kilometers away from A. the speed ratio of the two vehicles is known to be 3:2?
If the whole process is regarded as unit "1", then the distance between a and B is 60 (1-12 × 43) = 60 / 13, = 180 (km). The speed sum of a and B is 180 / 2 = 90 (km)
A and B leave from a and B at the same time and meet each other in two hours. After meeting, the two vehicles continue to move forward. When a arrives at B, B is 60 kilometers away from A. the speed ratio of the two vehicles is known to be 3:2?
If the whole process is regarded as unit "1", then the distance between a and B is 60 (1-12 × 43) = 60 / 13, = 180 (km). The speed sum of a and B is 180 / 2 = 90 (km)
A and B leave from ab at the same time and arrive at B for 5 hours. When B arrives at a for 6 hours, a runs 120 kilometers. How many meters does B run?
A and B leave from a and B at the same time. It takes 5 hours for a car to arrive at B and 6 hours for B car to arrive at a. when they meet, a car travels 120 kilometers. How many meters does B car travel? It's solved by one-step formula,
120 △ 6 × 5 = 100 km
A: B: 100 kilometers
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