![](data:image/svg+xml;utf8,<svg xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" viewBox="0 0 72 71" width="72"></svg>)
If the speed of a car from place a to place B is increased by 20%, it can arrive one hour earlier than the original time. If the speed is increased by 25% after driving 120 km at the original speed, it can arrive 40 minutes earlier______ Kilometers
If the speed is increased by 20%, the time will be 11 + 20% = 56, which is 1 hour earlier than the original time. If the speed is increased by 25%, the time will be 11 + 25% = 45. If the speed is increased by 40 minutes, the remaining journey will take 4060 △ 1-45 = 103 hours, which is 40 minutes earlier
If the speed of a car is increased by 20%, it can arrive one hour and 30 minutes earlier than the original time
If you increase the speed by 25% after 200 km, you will arrive 36 minutes earlier?
1 hour 30 minutes = 1.5 hours 36 minutes = 0.6 hours
Original time: 1.5 ÷ [1-1 / (1 + 20%)]
=1.5÷【1-5/6】
=9 hours
Original speed [200-200 (1 + 25%)] / [9-0.6-9 (1 + 25%)]
=【200-160】÷【9-0.6-7.2】
=40÷1.2
=100 / 3 km / h
The distance between a and B is 100 / 3 × 9 = 300 km
If the speed of a car is increased by 20%, it can arrive one hour earlier than the original time; if the speed is increased by 25% after driving 120 km at the original speed
You can arrive 40 minutes in advance. How many kilometers are there between a and B?
If the speed is increased by 20% (1 + 20% = 6 / 5), the time will be 5 / 6 of the original time. If the speed is reduced by 1 / 6, the original time will be 6 hours. If the speed of the whole journey is increased by 25%, the time will be reduced by 1 / 5. Therefore, the time will be reduced by 6 / 5 = 72 minutes and 72-40 = 32 minutes. The reason is that the whole journey is set to be x kilometers at the original speed of 120 kilometers
32/60:72/60=120:X,X=270
If the speed of a car from place a to place B is increased by 20%, it can arrive one hour earlier than the original time. If the speed is increased by 25% after driving 120 km at the original speed, it can arrive 40 minutes earlier______ Kilometers
If the speed is increased by 20%, the time will be 11 + 20% = 56, which is 1 hour earlier than the original time. If the speed is increased by 25%, the time will be 11 + 25% = 45. If the speed is increased by 40 minutes, the remaining journey will take 4060 △ 1-45 = 103 hours. If the speed is increased by 40 minutes, the time will be 103 △ 6 = 59, which is 103 △ 6 = 59 of the original time Cheng's (1-59), so the distance between a and B is 120 △ (1-59) = 270 km
RELATED INFORMATIONS
- 1. If the speed of a car from place a to place B is increased by 20%, it can arrive one hour earlier than the original time. If it travels at the original speed of 100 km, it can arrive again If you increase the speed by 30%, you will arrive one hour earlier than the original time. What is the distance between a and B?
- 2. If the speed of a car from a to B is increased by 20%, it will arrive one and a half hours earlier than the original time; if the speed is increased by 25% after 200 km, it will arrive 36 minutes earlier. How many kilometers are there between a and B
- 3. The distance between the two places is 81 kilometers. A and B ride from the two places at the same time. A rides 10 kilometers per hour, and the two meet after 4.5 hours. How much faster is a than B?
- 4. The distance between a and B is 100 kilometers. A rides a bicycle from a to B, Three hours after departure, B rides a motorcycle from a to B, and arrives two hours earlier than A. if B's speed is 2.5 times that of a, how many kilometers does a and B travel per hour
- 5. If the speed of a car is increased by 20%, it can arrive one hour earlier than the original time. If it is 5 kilometers faster than the original speed per hour, Then you can save 1 / 9 of the time. How many kilometers is the distance between a and B Then you can save 1 / 9 of the time. How many kilometers is the distance between a and B
- 6. If the speed of a car from place a to place B is increased by 20%, it can arrive one hour earlier than the original time. If the speed is increased by 25% after driving 120 km at the original speed, it can arrive 40 minutes earlier______ Kilometers
- 7. If the speed of a car from a to B is increased to 25%, it can arrive 25 minutes earlier than the original time. If the speed is increased to 1 / 3 after driving 80 km, it can arrive at B 10 minutes earlier to find the distance between a and B
- 8. What's the quickest setting for cement
- 9. There are two tons of cement. The first ton is 4.5 tons. It is known that one third of the weight of the first ton is equal to one fourth of the weight of the second pile. How many tons of cement is there in the second pile
- 10. Eight fifths of the cement sales of plant a is exactly three fifths of that of plant B. the sales of plant B is 1.2 million tons. How many million tons of cement are sold by plant a and plant B? Everyone help, there are reward points ~!
- 11. A car travels 60km per hour, 4 / 7 slower than a train. How many kilometers does a train travel per hour
- 12. A train can travel 80 kilometers per hour. How many hours and minutes does it take for this train to travel 50 kilometers?
- 13. A and B practice the 100m race. They start from the starting point at the same time. A's speed is 7m / s, B's speed is 6.5m/s. After running for 10s, a sprained his foot, If the velocity is reduced to 6m / s, can b catch up with a before reaching the 100m terminal? The solution of one variable linear equation is used,
- 14. In the 100 meter race between a and B, when a reaches the finish line, B is still 10 meters away from the finish line. If a retreats 10 meters from the starting point, who will reach the finish line first?
- 15. When a runs to the finish line, B is 10 meters away from the finish line. If a's starting line retreats 10 meters, the two race again at the same speed Who gets to the finish line first?
- 16. After braking, a stops 36m ahead within 3S, and B stops after 1.5s, then B advances
- 17. After braking at the same time, the two vehicles of a and B are moving in a straight line with uniform deceleration. A stops for 3 seconds and advances for 36 meters. B stops for 1.5 & nbsp; s. The forward distance of B is () A. 9 mB. 18 mC. 36 mD. 27 m
- 18. If the speed of car a and car B is equal, and the car decelerates evenly after braking, then the distance of car B is () A. 9 mB. 18 mC. 36 mD. 72 m
- 19. It is stipulated that the speed of a vehicle should not exceed 70 km / h on a certain highway. When a traffic accident occurs, the traffic police usually estimate the speed of the vehicle according to the sliding distance of the wheel after braking. The empirical formula used is v = 16 √ DF, where V is the vehicle speed (unit: km / h), D is the sliding distance of the wheel after braking (unit: m), and F is the friction factor, D = 20m, f = 1.2m, did the speed of the car exceed the specified speed?
- 20. From Jinan to Beijing, the actual distance is 490 km. The distance between the two places measured on a map is 4.9 cm