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If the speed of a car from a to B is increased by 20%, it will arrive one and a half hours earlier than the original time; if the speed is increased by 25% after 200 km, it will arrive 36 minutes earlier. How many kilometers are there between a and B
If the speed is increased by 20%, i.e. the original 1 + 20% = 6 / 5,
If the distance is the same and the time is inversely proportional to the speed, the time required becomes 5 / 6 of the original time,
It is known that it can arrive one and a half hours earlier than the original time = 1.5 hours,
It can be concluded that the original time is 1.5 (1-5 / 6) = 9 hours;
If the speed is increased by 25% after driving at the original speed of 200 km, that is, the speed becomes 1 + 25% = 5 / 4 of the original speed,
If the distance is the same and the time and speed are inversely proportional, the time required becomes 4 / 5 of the original,
It is known that in this way, we can reach the second place 36 minutes ahead of time = 3 / 5 hours,
It can be concluded that the original time for the rest of the journey after driving 200 km is (3 / 5) / (1-4 / 5) = 3 hours;
So it took 9-3 = 6 hours to drive 200 km at the original speed,
It can be concluded that the distance between a and B is 200 △ 6 × 9 = 300 km
If the speed of a car from a to B is increased by 20%, it can arrive one hour earlier than the original time; if it runs at the original speed of 40 km, it will arrive again
You can arrive 40 minutes earlier. How many kilometers are the two places apart
The distance between the two places is x kilometers, and the original speed of the car is y kilometers per hour
x/y-x/1.2y=1
(x-40)/y-(x-40)/1.25y=2/3
The solution is: x = 90, y = 15
A: the distance between a and B is 90 kilometers
If the speed of a car from a to B is increased by 20%, it can arrive one hour earlier than the original time; if the car runs at the original speed of 120 thousand kilometers
Then, how many kilometers is the distance between a and B? It's best to solve the equation. The equation of one yuan is the best
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If the speed from a to B is increased by 20%, the time will be 1 / (1 + 20%) = 5 / 6, reduced by 1 / 6, it will be 1 hour. So: the original time is 1 / [1-5 / 6] = 6 hours. If the original speed is x, the distance is 6x 120 / x + (6x-120) / [(1 + 25%) x] = 6-40 / 60 120 / x + 4.8-96 / x = 16 / 3 24 / x = 8 / 15 X
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