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There are two tons of cement. The first ton is 4.5 tons. It is known that one third of the weight of the first ton is equal to one fourth of the weight of the second pile. How many tons of cement is there in the second pile
B = 4.5 × 1 / 3 △ 1 / 4 = 6 tons
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There are 220 tons of cement in warehouse A and warehouse B. If Party A gives one third of it to Party B, and Party A is one fifth more than Party B, how many tons does Party A and warehouse B have?
A 220 / {(1-1 / 3) * [1 + 5 / (1 + 5)]} = 180 tons
B 220-180 = 40 tons
The original a 180 tons, B 40 tons
Each warehouse has some cement. The cement in warehouse A is 1 / 5 less than that in warehouse B. if 5 tons are transported from warehouse B and put into warehouse A, the cement in both warehouses will be the same. How many tons of cement did warehouse A and warehouse B have?
Upstairs. Look at the problem, you know he's in Grade 6. You get him binary equations. Don't feel trouble
If B warehouse x tons of cement, a warehouse (1-1 / 5) x = 4 / 5x tons
∴X-5=4/5X+5
The result is x-4 / 5x = 5 + 5
The solution is x = 50
A warehouse 4 / 5x = 40
Warehouse B 50 tons
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