The mass of a and B solid balls is greater than that of B. the relationship between the volume and density of a and B solid balls exists

The mass of a and B solid balls is greater than that of B. the relationship between the volume and density of a and B solid balls exists

The possible situations are as follows: V A is greater than V B, a density is greater than B density
V A is greater than V, B a density is equal to B density
V A is greater than V, B a density is less than B density
The density of V A is less than that of V B, and the density of a is greater than that of B
V A is less than V, B a density is equal to B density
The only impossible thing is that V A is less than V B, and the density of a is less than B

A and B are two solid balls. It is known that the density of a is greater than that of B. for the relationship between the mass and volume of a and B, can you name several possible relationships
We should give examples

When the mass of a and B is the same, the volume of a is large
When the volume of a and B is the same, the mass of a is larger

The solid balls are made of aluminum, iron and copper of equal mass, and their volumes are compared

The relative atomic mass of aluminum is 27, that of iron is 56, and that of copper is 64. Therefore, the volume of solid spheres made of aluminum, iron and copper with equal mass is in the order of aluminum, iron and copper

For an alloy ball, 2 / 3 of its mass is iron, and 1 / 3 of its mass is aluminum, its average density is calculated
The density of iron is 8g / cm3, and that of aluminum is 3G / cm3

The density of the alloy is as follows:
ρ=m/V=m/(V1+V2)=m/(m1/ρ1+m2/ρ2)
=m/[(2/3)m/ρ1+(1/3)m/ρ2]
=3ρ1ρ2/(ρ1+2ρ2)
=(3×8g/cm³×3g/cm³)/(8g/cm³+2×3g/cm³)
=14 g / cm and 179;. [approximate value]

Compared with iron and aluminum of equal mass, () has larger volume; compared with two solid metal balls of equal mass, () has higher density

Compared with iron and aluminum of equal mass, the smaller the density is, the larger the volume is; compared with 2 solid metal balls of equal mass, the larger the volume is, the smaller the density is

It is known that the density of iron is higher than that of aluminum. If iron and aluminum of equal mass are made into two metal balls respectively, and the volume of the two balls is also equal
Why must the iron ball be hollow
Please describe the process of pushing down_ ∩)o ...

If both are solid, the volume of the iron ball is small, because the volume is equal to the mass divided by the density. If the density is large, the volume is small. Now that the two volumes are the same, then the iron ball must be hollow, and the aluminum ball may not be

For copper, iron and aluminum spheres of equal volume and mass, if ρ Cu ＞ ρ Fe ＞ ρ Al is known, then ()
A. If the copper ball is solid, the other two balls must be hollow. B. if the iron ball is solid, the other two balls must be hollow. C. if the aluminum ball is solid, the other two balls must be hollow. D. all three balls may be hollow

If the three balls are all solid and equal in mass, ∵ ρ = MV, ρ copper ∵ ρ iron ∵ ρ aluminum, ∵ V aluminum ∵ V iron ∵ V copper and ∵ the three balls have the same volume, ∵ if the aluminum ball is solid, the other two balls must be hollow; if the aluminum ball is also hollow, the other two balls must also be hollow

There are two solid balls a and B. the density of ball a is 3 / 8 of that of ball B, and the volume of ball B is twice of that of ball A. then the mass of ball a is the same as that of ball B
Quantitative ()

The density of a is 3 / 8 of that of B, i.e. ρ a = 3 / 8 ρ B (1)
The volume of B is twice that of a, i.e. V A = 1 / 2 v b (2)
M a = ρ a * V A M B = ρ b * V B (1) * (2)
ρ a * V A = 1 / 2V b * 3 / 8 ρ B
M a = 3 / 16m B

For two uniform solid spheres A and B of equal mass, the ratio of their density is ρ A: ρ B = 1:2, then the ratio of their volume is V A: V B=_ ..
When they are still, the buoyancy ratio of water to the two balls is f a: F B = 6:5, then the density of a ball is ρ a=____ (known ρ water = 1.0 × 10 & # 179;, kg / M & # 179;)

V A: v b = 2:1 (density = m / V) if the two balls float on the water surface, the buoyancy ratio should be 1:1 (both equal to their gravity). If the two balls sink on the bottom, the buoyancy ratio should be 2:1 (buoyancy = density of water * drainage volume)

How to measure the volume, density and mass of an object with cup and water
The density of water is known

If it is floating, then: F floating = g matter = P liquid * g * V row
In the formula, "V row" can be measured by measuring cylinder, but "f floating, G object" should be measured by "spring scale" or "balance"
So, there are few conditions in the question
What's more, I don't know if the object can be put into the water