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The gas in a closed container is easy to be compressed, but after a certain mass of gas is compressed, its mass (), volume (), density () Bigger and smaller
unchanged
Smaller
enlarge
A certain mass of seal gas, when its volume is compressed, its density
Get bigger!
Density = what? Density = mass / volume
Compression mass unchanged, volume smaller, what do you say density will be?
Get bigger!
If there is 100 ml of gas in a closed container and its volume is compressed to 50 ml, the mass of the gas will be - Times (0,)
1 times, the quality will not change, hope to help you~
The teacher said that density is not affected by volume and mass. But why is a certain mass of gas sealed in a container? When its volume is compressed, its density will decrease
The teacher said that the density is not affected by the volume and mass. But why is a certain mass of gas sealed in the container? When its volume is compressed, its density will increase? Why is the same iron ball made of iron? The density of hollow iron ball is not as high as that of solid ball? T t is completely confused by the teacher's saying that the density does not affect the volume and mass
What I want to ask is: why do we calculate the density of the iron ball according to the formula, and then compare it with the density of the material ρ, if < ρ, then it is hollow, if = ρ, then it is solid density. Even the density of the uneven object is called average density. Then "calculate its density, and then compare it with the density ρ of the material, if < ρ" this part calculates the average density?
What the teacher said is a 1 ton iron block and a 100 ton iron block. The density of the two iron blocks is the same. You are right about the air example. The density of the "iron wall" of the hollow iron ball is the same as that of the solid iron ball
There is 1 liter of gas in a closed container. When its volume is compressed to 0.5 liter, the density of the gas is the same as before______ Times
After a certain mass of gas is compressed, the amount of matter remains unchanged, so the mass remains unchanged; when the other volume of 1l is compressed to 0.5L, the volume becomes half of the original. According to ρ = MV, when the mass is fixed, the density is inversely proportional to the volume, so the density of the gas becomes twice of the original. So the answer is 2
For a certain mass of loose bar, when its volume v = 2 cubic meters, its density p = 0.5x10 to the third power, then the functional relationship between P and V is
m=pv=0.5x10^3x2=1000Kg
p=m/v=1000/v
When the mass is constant, the volume V of carbon dioxide is inversely proportional to the density p, and when v = 5m cubic, P = 1.98kg/m cubic
(1) Find the function relation between P and V, and point out the value range of independent variable
(2) The density of carbon dioxide when v = 9m cubic
(1)m=ρv=1.98×5=9.9
9 / V, and the value range of V is v > 0
(2) Substituting v = 9 into ρ = 9.9/v, we get
ρ=9.9/9=1.1(kg/m³)
It is known that the functional relationship between density p (kg / m3) and volume V (M3) of carbon dioxide is p = 9.9/v
1) When v = 5 m3, the density of carbon dioxide is p
2) It shows that the density p of carbon dioxide changes with the increase or decrease of volume v
p=9.9/5=1.98kg/m3
When the volume of CO2 increases, the density decreases, the volume decreases and the density increases
For a certain mass of carbon dioxide, when its volume v = 5m, its density q = 1.98kg/m
(1) (2) when v = 9m, what is the density Q of carbon dioxide?
(1) M = QV = 1.98kg/m × 5m = 9.9kg the function formula is q = 9.9/v (2) when v = 9m, q = m / v = 9.9kg/9m = 1.1kg/m
For a certain mass of carbon dioxide, when its volume v = 5m & sup3; and its density ρ = 1.98kg/m & sup3 (1), the density of carbon dioxide when v = 9m & sup3; can be calculated
The density p (2) gives the function expression of P and V
M = ρ V constant
（1）ρ2=ρV/v=1.1kg/m³
（2）ρV=1.98*5=9.9
ρ=9.9/V
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