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Density is independent of its mass and volume Why? If the volume is larger, the density will be smaller. If the mass is larger, the density will also be larger. Why is this irrelevant?
Density is a property of matter itself, independent of mass and volume
The relationship between density and molecular weight
It can be seen from this that the higher the density is, the greater the molecular mass will be for both liquids and gases at the same concentration, and the simpler the solid is. The higher the density is, the greater the molecular mass will be for both liquids and gases at the same volume
What is the relationship between mass and density
Mass is the product of density and volume
m=ρV
What is the relationship between density and mass and volume
Mass equals density times volume
Relationship between mass and bulk density
A tanker carries 40 cubic meters of oil. Take 30 square centimeters of oil from the tanker and weigh it to 25.5 grams. Find out the mass of oil in the tanker
Why is it right or wrong?
Not true. The square centimeter is a unit of area and has no direct relationship with mass, so there is no solution to this question
Is the density ρ of water the same as the weight γ of water?
Weight of different water = density of water × acceleration of gravity
When G is taken as 10, the weight of water is the fourth power of 10
What is the meaning of water density
Water density: 1.0 * 10 ^ 3kg / m ^ 3
Meaning: the mass of water with volume of 1m ^ 3 is 1.0 * 10 ^ 3kg
Definition: in physics, the mass per unit volume of a substance is called its density
What is the relationship between gas density and molecular number
Density = m / 22.4 M = MNA / n n n is the number of molecules Na is the Avogadro constant M is the relative molecular mass m is the mass
The natural density of undisturbed soil sample P = 1.67g/cm3, water content w = 12.9%, specific gravity GS = 2.67, porosity ratio e, saturated density psato
Let v = 1, M = 1.67
ms+mw=1.67,mw/ms=12.9%
The results show that Ms = 1.48, Mw = 0.19, VW = 0.19,
Gs=ms/vs*r(w)4℃
554, VV = 1-0.19-0.554 = 0.256
e=Vv/Vs=0.256/0.554=0.462
p=（ms+Vv*pw）/V=（1.48+0.256*1）/1=1.736
I don't know if there are any mistakes. It should be right
In geotechnical investigation, given the natural density, dry density, saturation and water content from geotechnical test, how to calculate the saturated density?
Given the wet soil m (g), water content w (%) and dry soil weight g, calculate the dry density (g / g) / m, calculate the wet density equal to the dry density divided by (1 W), calculate the compactness equal to the ratio of the calculated dry density and the known dry density
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