Square of (vector a×vector b)=? Vector a* absolute value of vector b Square of (vector a×vector b)=? Absolute value of vector a* vector b

Square of (vector a×vector b)=? Vector a* absolute value of vector b Square of (vector a×vector b)=? Absolute value of vector a* vector b

R is the angle between two vectors, a×b=absinr
(A×b)^2= a^2*b^2*(sinr)^2
A. b=abcosr
|A.b|=ab|cosr|

Square of absolute value (vector a + vector b)+ square of absolute value (vector a-vector b)+2 times (square of absolute value of vector a + square of absolute value of vector b) How to construct a graph to explain the geometric meaning of the formula

Sum of squares of the diagonals of a parallelogram
Equal to the sum of the squares of the four edges
This can be proved. It's a theorem.
Forget about it. Or it's a rectangle.
It should be equal, not what you say

Sum of squares of the diagonals of a parallelogram
Is the sum of the squares of the four sides
This can be proved. It's a theorem.
Forget it, or it's a rectangle.
It should be equal, not what you say

If the absolute square of vector a is equal to one, and the absolute square of vector b is equal to 2,(a-b)⊥a, then the angle between a and b is?

Because (a-b) is perpendicular to a,(a-b)*a=0
A^2-ab=0
A^2-a*b*cos=0
It should be.
The module square of vector a is equal to one and the module square of vector b is equal to 2
Then modulus of a =1, modulus of b = root number 2
That is,1- root 2*cos=0
Cos = root 2
Then, the included angle of ab is 45°

Because (a-b) is perpendicular to a,(a-b)*a=0
A^2-ab=0
A^2-a*b*cos=0
It should be.
The module square of vector a is equal to one and the module square of vector b is equal to 2
Then modulus of a =1, modulus of b = root number 2
That is,1- root 2*cos=0
Cos =2
Then, the included angle of ab is 45°

If the vector a, b, c satisfies a+b+c=0 and a is vertical b, the absolute value a=1, the absolute value b=2, then the square of the absolute value c is equal to?

|C|^2=|-a-b|^2=|a+b|^2=|a|^2 b|^2+2ab=1^2+2^2+2*0=5

Is the absolute value of a+b less than or equal to the absolute value of a plus the absolute value of b a b vector pair

0

Given the nonzero vectors a, b, if a+2b is perpendicular to a-2b, then |a|/|b| equals

Because it is vertical,(a+2b)*(a-2b)=0, i.e. a-square-4b-square=0, a-square/b-square=4,|a|/|b|=root4=2