Vector a=3i-j-2k, b=i+2j-k, then (-2a) point times 3b= I'm Xiao Bai.

Vector a=3i-j-2k, b=i+2j-k, then (-2a) point times 3b= I'm Xiao Bai.

(-2A) point by 3b
=3×1+(-1)×2+(-2)×(-1)
=3-2+2
=3

Let vector a=3i-j+2k, vector b=i+2j+k, calculation:(1)(-2a)*(3b)(2)3a*2b The letters in parentheses are all vectors. (1) Is dot multiplication,(2) is cross multiplication,

If it's a dot.
(1)-18
(2)18
Cross multiplication is
(1)(-18,12,-12)
(2)(18,-12,12)

If it's a dot, multiply it.
(1)-18
(2)18
Cross multiplication is
(1)(-18,12,-12)
(2)(18,-12,12)

Point A (-2,1), point B (-1,3), the coordinates of vector AB?

AB=B-A=(1,2)

The product of the quantity of the space vector, the formula of the length of the module and the formula of the determination of the perpendicularity RT, used to solve the problem of solid geometry, set the vector a=(x1, y1, z1), b=(x2, y2, z2), find their coordinate operation formula Finding the Product of Quantity of the Vector of Question Space, the Formula of Module Length and the Formula of Determination of Verticality RT, used to solve the problem of solid geometry, let vector a=(x1, y1, z1), b=(x2, y2, z2), find their coordinate operation formula

Vector a=(x1, y1, z1), b=(x2, y2, z2),
Product of quantity ab=x1x2+y1y2+z1z2
Vector a modulus length formula =√(x12+y12+z12)
A, b vertical equivalent to ab=0, i.e. x1x2+y1y2+z1z2=0

CONDITIONS FOR VERTICAL SPACE VECTORS How are (a1, b1, c1) and (a2, b2, c2) perpendicular?

A1a2+b1b2+c1c2=0

If vector a is perpendicular to vector (b-c), then a*b=a*c?

Equals vector a perpendicular to vector (b-c), then a (b-c)=0 a*b-a*c=0