Note again whether it is a vector or a scalar Rate, Average rate Then indicate whether it is a vector or a scalar Rate, Average rate

Note again whether it is a vector or a scalar Rate, Average rate Then indicate whether it is a vector or a scalar Rate, Average rate

1: How much distance an object passes through per unit time, vector
2: Scalar value of the ratio of the distance the object moves to the time it takes to move
3: In variable speed linear motion, the ratio of the displacement s of the moving object to the time t is called the average velocity vector of the time (or displacement)
4: The average velocity is the scalar quantity of the ratio of the distance the object moves to the time it takes to move

Is Instantaneous Velocity a Vector or a Scalar? Isn't speed supposed to be a concept of bit removal over time? Why is instantaneous speed calculated by dividing distance by time?

When did the instantaneous speed become distance divided by time?
Velocity is a vector, whether average or instantaneous.
It is difficult to calculate the instantaneous velocity in the first stage, so the formula can only be used to calculate the instantaneous velocity of uniform motion or uniform linear motion.
Average speed = bit removed in time.
Average speed = distance divided by time. This is scalar, and this is actually the concept of speed in junior high.

When did the instantaneous speed become distance divided by time?
Velocity is a vector, whether average or instantaneous.
It is difficult to calculate the instantaneous velocity in a higher stage.
Average speed = bit removed in time.
Average speed = distance divided by time. This is scalar, and this is actually the concept of speed in junior high.

When did the instantaneous speed become distance divided by time?
Velocity is a vector, whether average or instantaneous.
It is difficult to calculate the instantaneous velocity in the higher stage, so the formula can only be used to calculate the instantaneous velocity of uniform motion or uniform linear motion.
Average speed = bit removed in time.
Average speed = distance divided by time. This is scalar, and this is actually the concept of speed in junior high.

Ampere force f=qvbf is the vector scalar by scalar vector by vector is scalar scalar by vector is vector Ampere force f=qvb F is a vector The scalar is multiplied by the scalar Vector multiplication vector is scalar Scalar Multiply Vector Is Vector That's it. F becomes a scalar Talk about time and distance S=vt also non-conforming Ampere force f=qvbf is the vector scalar by scalar vector by vector is scalar scalar by vector is vector Ampere force f=qvb F is a vector That scalar is multiplied by a scalar Vector Multiply Vector Is Scalar Scalar Multiply Vector Is Vector That's it. F becomes a scalar Talk about time and distance S=vt also non-conforming

Where v is a vector, q, b is a scalar, so the multiplied f is a vector. The distance s=vt, where v is not a vector, should be the average speed, do not confuse, so the distance s is also a scalar. If it is displacement s=vt, where v is a vector, is the average speed, so displacement s is a vector

Where v is a vector, q, b is a scalar, so the multiplied f is a vector. The distance s=vt, where v is not a vector, should be the average speed, do not confuse, so the distance s is also a scalar. If displacement s=vt, where v is a vector, is the average speed, so displacement s is a vector

When we learn vectors, we know that velocity is also a vector, but in the difference between vector and scalar, there is a vector can not be directly added or subtracted, which is generally in the problem of acceleration or other speed-related quantities, can not be added or subtracted? When we learn vector, we know that velocity is also a vector, but in the difference between vector and scalar, there is a vector can not be directly added and subtracted, which is generally in the problem of acceleration or other speed-related quantities, can not be added or subtracted? When we learn vector, we know that velocity is also a vector, but in the difference between vector and scalar, there is a vector can not be directly added or subtracted, which is generally in the problem of acceleration or other speed-related quantities, can not be added or subtracted?

For example, Xiao Min throws a ball horizontally at a speed of 2 meters per second from the air to find the speed of the ball after 4S (the ball does not land at 4S). We know the acceleration formula v=v0+at, but here we can not directly use 2+4g (g is the acceleration of gravity). In this motion, the ball only receives the acceleration g from the earth, but the acceleration is different from the direction of velocity. One is always vertical and downward. Therefore, we can not add and subtract directly with the formula. At this time, we can divide the motion into a horizontal uniform speed straight line and a uniform acceleration straight line. Use the appropriate formula according to different situations. Finally, use the vector triangle ball to give the final answer (note the direction). Sometimes, you can also use the triangle function to decompose the force or acceleration according to the parallelogram rule to make the acceleration and the speed in the same direction, and then directly add and subtract. I hope it will help you ~

The Expression of Vectors of Various Centers of High School Mathematical Triangle Center of gravity, center of gravity, inner, outer The Expression of Vector of Various Centers of High School Mathematical Triangle Center of gravity, center of gravity, inner, outer The Expression of Vectors of Various Centers of High School Mathematical Triangle Center of gravity, center of gravity, heart, heart

The necessary and sufficient conditions on the plane of ⊿ABC and the opposite sides of angles A, B and C be a, b and c respectively, then 1. If vector OA=vector OB=vector OC, then O is the outer center of ⊿ABC. If vector OA+vector OB+vector OC=0, then O is the center of gravity of ⊿ABC. If vector OA•vector OB=...

The necessary and sufficient conditions on the plane of ⊿ABC and the opposite side lengths of angles A, B and C be a, b and c, respectively, then 1. If vector OA=vector OB=vector OC, then O is the outer center of ⊿ABC. If vector OA+vector OB+vector OC=0, then O is the center of gravity of ⊿ABC. If vector OA•vector OB=...

The necessary and sufficient conditions on the plane of ⊿ABC and the opposite sides of angles A, B and C be a, b and cC is located, and the opposite side lengths of angles A, B and C are a, b and c respectively.1. If vector OA=vector OB=vector OC, then O is the outer center of ⊿ABC.2. If vector OA+vector OB+vector OC=0, then O is the center of gravity of ⊿ABC.3. If vector OA•vector OB=...

1. Given the quadrilateral ABCD, the points E, G and H are the midpoint of AB, BC, CD and DA respectively. 2. Determine the shape of the quadrilateral ABCD according to the following conditions and give proof: (1) AD=BC (2) AD=(1/3) BC (3) AB=DC, and |AB|=|AD| Because the vector arrows above the letters don't come out, you know the arrows.

1: Proof: respectively connect EF, AC and HG
Because E, F are the midpoint of AB, BC, respectively
So EF is the median line of triangle ABC, i.e. vector EF =1/2 vector AC
Similarly, vector HG=2/1 vector AC
So vector EF = vector HG;
2:(1): Parallelogram proof: because vector AD = vector BC,(vector has direction, if two vectors are equal, then two sets of sides are parallel)
AD//=BC; defined by parallelogram
(2): Trapezoidal proof:(if only the direction is the same, then a group of sides are parallel)
According to the trapezoidal definition
(3): Ling-shaped proof: AB=DC is the same as the proof in (1), so there is no more explanation.
And |AB|=|AD|, the adjacent edges are equal,
According to the definition of a shape, a parallelogram with an equal set of adjacent edges is a shape