The absolute value of vector a is known to be equal to root number 2, the absolute value of vector b is known to be equal to root number 3, and the angle between vector a and vector b is 45 degrees Find the value range of λ whose angle between a vector b vector and λa vector +b vector is an acute angle. The absolute value of vector a is known to be equal to root number 2, the absolute value of vector b is known to be equal to root number 3, and the angle between vector a and vector b is 45 degrees The the value range of λ whose angle between a vector b vector and λa vector +b vector is an acute angle.

The absolute value of vector a is known to be equal to root number 2, the absolute value of vector b is known to be equal to root number 3, and the angle between vector a and vector b is 45 degrees Find the value range of λ whose angle between a vector b vector and λa vector +b vector is an acute angle. The absolute value of vector a is known to be equal to root number 2, the absolute value of vector b is known to be equal to root number 3, and the angle between vector a and vector b is 45 degrees The the value range of λ whose angle between a vector b vector and λa vector +b vector is an acute angle.

The inner product of two vectors is equal to the product of the modulus length (absolute value) and the sine and cosine value of the included angle. Therefore, the inner product is required to be positive.(The case of the same direction must be excluded at the same time)(a b)(λa+b)= a^2+(2+1) ab b^2=2(2+1) root sign 2* root sign 3* root sign 2/2+3λ= root sign 3 2+5 root sign 3>0. The solution is:λ>(-)

The inner product of two vectors is equal to the product of the modulus length (absolute value) and the sine and cosine value of the included angle. Therefore, the inner product is required to be positive.(The case of the same direction must be removed at the same time)(a b)(λa+b)= a^2+(2+1) ab b^2=2(2+1) root sign 2* root sign 3* root sign 2/2+3λ= root sign 3 2+5 root sign 3>0. The solution is:λ>(-)

Given the vector a=(2,1), a*b=10, the absolute value of a+b =5, find the absolute value of b?

Let b=(x, y) have 2x+y=10 and (2+x)^2+(1+y)^2=50, then x=3y=4
Therefore, the absolute value of b is 3*3+4*4=5 under the root

Given vector a=(2,1) vector a×vector b=10 absolute value of vector a+b=5,2, the absolute value of vector b is Given vector a=(2,1) vector a×vector b=10, the absolute value of vector a+b 2, the absolute value of vector b is Given vector a=(2,1) vector a×vector b=10, the absolute value of vector a+b=5,2, the absolute value of vector b is

Let: b=(x, y)
Then: a*b=2x+y=10
|A+b|^2=(x+2)^2+(y+1)^2=50
X^2+4x+4+y^2+2y+1=50
X^2+y^2=45-2(2x+y)=45-20=25
|B |^2= x^2+y^2=25
|B |=5

The absolute value of vector a =1 and the absolute value of vector b = root 3 vector a + vector b =(root 3,1) are known (1) Find the vector a-vector b|(2) Find the angle between vector a+vector b and vector a-vector b The absolute value of vector a =1 and the absolute value of vector b = root number 3 vector a + vector b =(root number 3,1) are known (1) Find the vector a-vector b|(2) Find the angle between vector a+vector b and vector a-vector b

(1)|A|=1,|b|=√3 a+b=(√3,1)(a+b)2=a2+2ab+b2=1+2ab+3=4, so ab=0|a-b|2=a2-2ab+b2=1+3=4, so a-b|=2(2)(a+b)(a-b)=a2-b2=1-3=-2|a+b|=2, so cosθ=[(a+b)(a-b)]/[...

Is energy scalar or vector Since there are "negative" and "positive" energies, is energy scalar or vector?

Energy is a scalar; Scalar: There is only size, no direction vector: there is both direction and size. Think about it, how can energy have a direction? To distinguish, the transfer of energy, energy can be transferred from one object to another. However, energy does not have a direction, but objective existence of size. You might see that there is...

Energy is scalar; Scalar: only size, no direction vector: both direction and size. Think about it, how can energy have a direction. To distinguish, the transfer of energy, energy can be transferred from one object to another. But energy does not have a direction, but the objective existence of the size. You may see energy in front of the...

Is kinetic energy scalar or vector

Scalar quantity