Maths Senior One 》》》 The following lowercase letters are all vectors If the nonzero vector a, b satisfies |a+b|=|b|, then... ( ) (A)|2a|>|2a+b| (B)|2a||a+2b| (D)|2b|

Maths Senior One 》》》 The following lowercase letters are all vectors If the nonzero vector a, b satisfies |a+b|=|b|, then... ( ) (A)|2a|>|2a+b| (B)|2a||a+2b| (D)|2b|

Select the special value method:
Suppose a, b vector direction is opposite.|a|=2|b|=1
Bring in 4 options to select the qualified ones.
A. Definitely right. Just do it. Efficiency comes first.

Select the special value method:
Suppose a, b vector direction is opposite.|a|=2|b|=1
Bring in 4 options to select the qualified ones.
A. It's right. Just do it. Efficiency comes first.

Vector computation problem Given that the vector a, b satisfies (a+2b)×(a-b)=-6, and the module of a =1, the module of b =2, the angle between a and b is Given that triangle ABC is isosceles triangle, angle C=90°, AB=4, then vector AB×vector BC=

1|A|=1,|b|=2(a+2b)·(a-b)=|^2-2|b|^2+a·b=1-8+a·b=-6, i.e. a·b=1, i.e. cos=a·b/(|a b|)=1/2, i.e.=π/32BC projection on BA:|BC|cosB=2, i.e.|BC|=2/cosB=2/cos (π/4)=2√2, i.e. AB·BC=|AB BC|* cos (π-π/4)=4*2√2...

Space Vector and Its Application 1 In the known cuboid ABCD-A1B1C1D1, E and F are the points on A1D and B1D1, respectively, and A1E/A1D=B1F/B1D1.

Take K on D1D and make D1K/KD=A1E/ED, then EK//A1D1. Similarly, take a point T on D1C1 and make FT//B1C1, then EK//A1D1//B1C1//FT.EK/A1D1=DE/A1D=D1F/D1B1=FK/B1C1. Then A1D1=B1C1, then EK=FT, EKTF is parallelogram, EF//KT, KT is on C1CDD1, EF is not on C1CDD1.

Fast and skillful calculation 192192*368-368368*192

192*368*1001-368*1001*192=0

Fast and skillful calculation of sixth grade mathematical thinking training (1)73 Of 17 divided by 9(2)2222*1.7+3333*0.4+6666*0.9

(72+17/18)*1/9Th
1111*3.4+1111*1.2+1111*5.4
=1111*(3.4+1.2+5.4)
That's enough, right?

(72+17/18)*1/9
1111*3.4+1111*1.2+1111*5.4
=1111*(3.4+1.2+5.4)
All right?

The vector follows the parallelogram rule. So what is the parallelogram rule?

When two forces are combined, the line segment representing the two forces is used as a parallelogram, and the diagonal between the two adjacent sides represents the magnitude and direction of the resultant force, which is called parallelogram rule