In extracurricular activities, four people report the number. A says: 1. B says 2, C says 3, and Ding says 4. In this way, the total number of people reported is more than money. Ask 34 who reported it. 71 who reported it

In extracurricular activities, four people report the number. A says: 1. B says 2, C says 3, and Ding says 4. In this way, the total number of people reported is more than money. Ask 34 who reported it. 71 who reported it

34 divided by 4 equals 8 plus 2, so it's B

If there are 2014 students in a row and report according to the rule of 1,2,3,4,3,2,1., then the number reported by the 2014 student is (?)

Because every six numbers are a round, 1, 2, 3, 4, 3, 2, and then divide 2014 by 6 to see the remainder to determine the answer
2014÷6=335…… Four
So the number reported by the 2014 student was 4

Four students, a, B, C and D, form a circle and report the numbers in order ① A, B, C, d first reported the number is 1, 2, 3, 4, then a report 5, B report 6 According to this rule, the number reported by the last student is larger than that reported by the previous one. When the number reported is 50, the report ends; ② If the number quoted is a multiple of 3, the student who reported the number should clap his hands once. In this process, the number of times a student needs to clap his hands is______ .

∵ the numbers reported by a, B, C and D for the first time are 1, 2, 3, 4 in turn According to this rule, the number reported by the latter student is larger than that reported by the previous student. When the number reported is 50, the report ends;  50 ﹤ 4 = 12, 2,  a totally reported 13 times, respectively 1, 5, 9, 13, 17, 2

There are 2012 students standing in a row to report the number, odd number back, even number to stay, and so on, the remaining students continue to count

1024 Oh, remember to add points Oh! The first time the remaining people, in the initial number is 2,4,6,8,10,12,..., are multiples of 2, (down 1006 people, there are 1006 people left) the second time the remaining people, in the initial number is 4,8,12,16,20,,, are all multiples of 4, (and down 503 people, there are still

1. 2010 students stood in a row and counted out. The odd number left, the even number left, and the remaining students did not move to count again, 1. 2010 students stand in a row and report to the odd number to quit, even number to stay, the left students' position will not move to count again, report to odd number exit, even number to stay, so continue, and finally leave one student, what is the position of the last left student standing for the first time? 2. Fold a rectangular piece of paper ABCD as shown in the figure. The crease is EF, and the points c and d fall on C'd '. If ∠ bef = 65 ° is known, what degree is ∠ BEC'? 3. Clocks are timing tools in daily life. We can find that there are many mathematical contents in clocks and clocks. At a certain moment between 9:00 and 10:00, Xiao Ming finds that the hour hand and minute hand coincide. What time is it?

1. The last remaining student is No. 1024. After the first screening, the remaining one is a multiple of 2, and the remaining one after the second screening is a multiple of 4, then only 1024 is left after the tenth screening
2. No picture
3. Suppose that the nine o'clock coincides with the minute hand at 30 ° for one hour, then 0.5 ° for one minute, and 360 ° for minute hand for one hour, then 6 ° for one minute. At nine o'clock, the angle formed by the hour hand and 12 o'clock is 90 ° - 0.5 ° * x, and the angle formed by minute hand and 12:00 is 360 ° - 6 ° * x, both of which are equal, x = 540 / 11

There are 50 students in a row, report even number to stay, report odd number to leave; left students continue to count, report even number continue to stay, report odd The number of left, until only one student left, the last remaining students should stand in the original team where?

By using permutation method, it can be found that the person who goes for the first time is a multiple of 2, that is, the power of 2; for the second time, it is a multiple of 4, that is, the square of 2; for the third time, it is a multiple of 8, that is, the third power of 2. And so on, the last person left is the n power of 2, and the result is the number closest to 50, that is, the fifth power of 2: 32, The number of people who stay at last is the n power of 2, which is the number closest to the total number of people. Of course, if you walk 3, 4, 5 each time Similar laws can also be found

Twenty students lined up in a row, and the first one started to count. The odd number students dropped out of the team, while the even number students did not move, Then start counting from the beginning again. If you go on like this, the last one who says even is the winner. What position should you stand in the queue for the first time to win?

You don't put 20 dots on the number axis, take out the odd numbers one by one, and the last one is exactly at position 16

There are 2013 students standing in a row from left to right, counting from 1, reporting odd number of retreat, even number of left, left students There are 2013 students standing in a row, from left to right, counting from 1 in turn, reporting odd number of retreat, even number left, left students' position unchanged, from left to right, counting from 1 in turn, reporting odd number down, even number remaining,..., so on, and finally leaving a fellow student, the last remaining student's first standing position is

After n rounds (n is a positive integer), the number of the remaining students is 2n;
∵ 2n ≤ 2011, that is, n ≤ 11,
When there is only one person left in the circle, n = 10, the student's number is 2n = 210 = 1024.. the answer is 1024 digits
I hope my answer can help you,

300 students in a row, according to the following rules from front to back; if a student reported a single digit, the latter student should report the number of 8 If a student reported a 2-digit number, the last student should report the sum of the number of digits and 3. If the first student reported one, what was the last student's report?

The law of counting is as follows:
1,9,17,0,8,16,9,17,0,8,16,9. The number of the 300th student should be: (300-1) × 5 = 59.4
The number is: 8

999 students are arranged in a row from front to back and count off according to the following rules: If the number reported by a student is one digit, then the following students should report the sum of this number and 9; if a student's number is two digits, then the following students should report the sum of each number and 6. Now let the first student report 1, then what is the number of the last student?

The number reporting rule 1,10,6,15,11,7,16,12,8,17,13,9,18,14,10, returns to 10. Therefore, in addition to the first number, the 13 numbers are a cycle, so (999-1) / 13 = 76, the remainder of 10, so the 999 number is 13