![](data:image/svg+xml;utf8,<svg xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" viewBox="0 0 72 71" width="72"></svg>)
Given that the perimeter of a right triangle is 30 and the area is 30, find the oblique side length of the triangle
a+b+c=30
ab/2=30
a ²+ b ²= c ²= (a+b) ²- 2ab=(30-c) ²- 120=c ²
=>>c=13
The circumference of a right triangle is 30 and the length of the hypotenuse is 13. What is the area of this right triangle? Speed up and help me
The circumference of a right triangle is 30 and the length of the hypotenuse is 13. What is the area of this right triangle?
Let the two right angle sides be a and B
A+B=30-13=17
(A+B)^2=17*17
A^2+B^2+2AB=289
According to Pythagorean theorem: A ^ 2 + B ^ 2 = 13 ^ 2 = 169
2AB=289-169=120
AB=60
Area s = 1 / 2 * AB = 30
The perimeter of a right triangle is 30 and the center line on the hypotenuse is 6.5. The detailed process of finding the area of this triangle (using Pythagorean theorem)
Because the center line on the beveled edge is 6.5, the length of the beveled edge is 13
Let the side lengths of two right angles be a and B respectively
Therefore, a + B + 13 = 30, that is, a + B = 17
According to Pythagorean theorem, a ²+ b ²= thirteen ²
（a+b） ²- 2ab=13 ²
Area = 1 / 2Ab = 30
The circumference of a right triangle is 30cm and the length of the hypotenuse is 13cm. Find the area of this triangle
Suppose the height of the triangle is x, one side is known to be 13 cm, and the circumference of the triangle is 30 cm, then the length of the third side is 30-13-x
According to the triangle Law:
Square of X + (30-13-x) square = 13 square
Square of X + 289 + square of X - 34x = 169
Square of X - 17x = - 60
Square of X - 17x + 60 = 0
Multiply by the cross:
X = 3, x = - 20 (rounded)
So the height of the triangle is 3, the bevel is 13 and the bottom is 14
The area of a triangle is: the bottom edge times the height divided by 2 = 14 times 3 divided by 2 = 21
A: the area of the triangle is 21 square centimeters
The area of the triangle surrounded by the straight line y = 2x-3 and the two coordinate axes is equal to?
Let x = 0, then y = - 3
If y = 0, x = 3 / 2
｜x｜ × ｜ y｜÷ 2 = 3 × 3/2 ÷ 2 = 9/4
The area of the triangle is equal to 9 / 4
If the area of the triangle enclosed by the straight line y = 2x + m and the two coordinate axes is equal to m, find the value of M
y=2x+m
When x = 0, y = m
When y = 0 x = - M / 2
Area = |m| * | - M / 2| / 2 = m
m ²= 4m
Because area = m ≠ 0
So m ²= 4m m=4
RELATED INFORMATIONS
- 1. If the area of the triangle enclosed by the straight line y = 2x + m on the two coordinate axes is equal to m, the value of M is
- 2. The lengths of both sides of the triangle are 8 and 6 respectively. The length of the third side is a real root of the univariate quadratic equation x2-12x + 20 = 0. Find the area of the triangle
- 3. The slope of the straight line L is known to be 1 6, and forms a triangle with an area of 3 with the two coordinate axes, then the equation of straight line L is __
- 4. The area of a triangle is 48cm2, and the area of the triangle surrounded by its three median lines is
- 5. In △ ABC, it is known that BD and CE are the midlines on both sides respectively, and BD ⊥ CE, BD = 4, CE = 6, then the area of △ ABC is equal to () A. 12 B. 14 C. 16 D. 18
- 6. Draw four small triangles in the square (as shown in the figure). The area ratio of triangles I and II is 2:1; The areas of triangles III and IV are equal; The sum of the areas of triangles I, II and III is 1 4 square meters; The sum of the areas of triangles II, III and IV is 1 6 square meters; So what is the sum of the four small triangles______ Square meters
- 7. The three sides of a right triangle are 3cm, 4cm and 5cm respectively. The area of this triangle is () square centimeters; The height on the hypotenuse is () cm Such as the title! Urgent~
- 8. The three sides of a right triangle are 3cm, 4cm and 5cm respectively. How many square centimeters is the area of the right triangle?
- 9. Given that the lengths of both sides of the triangle are 5 and 7 respectively, the value range of the center line length x of the third side is () A. 2＜x＜12 B. 5＜x＜7 C. 1＜x＜6 D. Unable to determine
- 10. Given that the lengths of both sides of the triangle are 5 and 7 respectively, the value range of the center line length x of the third side is () A. 2＜x＜12 B. 5＜x＜7 C. 1＜x＜6 D. Unable to determine
- 11. If the perimeter of a right triangle is 5cm and the center line on the hypotenuse is 1cm, the area of this right triangle is?
- 12. In △ ABC, a = 60 °, C: B = 8:5, the area of the inscribed circle is 12 π, and the radius of the circumscribed circle of △ ABC is calculated
- 13. It is known that in △ ABC, the side opposite the acute angle B = 7, the radius of the circumscribed circle r = 7 times the root number 3 / 3, and the triangle area s = 10 times the root number 3. Find the length of the other two sides of the triangle
- 14. In triangular row ABC, a equals 1, C equals 2, and B equals 60 degrees. What is the area of triangular ABC
- 15. In the acute triangle ABC, the opposite sides of angles a, B and C are a, B and C respectively, and the root number 3B = 2asinb is known to calculate the size of the angle; If a = 6, find the range of B + C
- 16. Cut out a square as large as possible, the largest square, from an isosceles right triangle cardboard with an inclined edge of 18cm long What is the side length of the?
- 17. As shown in the figure, the side length of the regular triangle ABC is 6. Cut off three corners to get a regular hexagon. Find the side length and area of the regular hexagon
- 18. As shown in the figure, the length of the rectangle is 6cm, the width is 4cm, and the area of the shaded triangle is 9cm2. Find the length of BD. how to prove the vertical length of be
- 19. In △ ABC, the opposite sides of angles a, B and C are a, B and C respectively, and meet 2C − B a＝cosB cosA． (I) find the size of angle a; (II) if a = 2 5. Find the maximum value of △ ABC area
- 20. As shown in the figure, in triangle ABC, ab = AC = 20, angle B is equal to 15 degrees, then the area of triangle ABC