If the area of the triangle enclosed by the straight line y = 2x + m on the two coordinate axes is equal to m, the value of M is

If the area of the triangle enclosed by the straight line y = 2x + m on the two coordinate axes is equal to m, the value of M is

y=2x+m
y=0,x=-m/2
x=0,y=m
Therefore, area = | - M / 2| * | m ÷ 2 = m
m ²= 4m
The area is greater than 0, so it is not equal to 0
Both sides divided by M
m=4

The area of the triangle enclosed by the straight line y = 2X-4 and the two coordinate axes is equal to () A. 2 B. 4 C. 6 D. 8

When x = 0, y = - 4,
When y = 0, x = 2,
The area of the triangle = 1
two × two ×|- 4|=4．
Therefore, B

The straight line y = 2x + 4, and the area of the triangle surrounded by the two coordinate axes is equal to? A. 4 square units B.6 square units c.8 square units d.10 square units

∵ the straight line y = 2x + 4, and the intersection with the two coordinate axes is (- 2,0) (0,4)
∴S＝1/2 × two × 4＝4
‡ select a

In the rectangular coordinate system, the straight line L passes through two points a (a, 0) and B (0, - 2), and the area of the triangle surrounded by the straight line L and the two coordinate axes is equal to 10 (1) Draw △ OAB; (2) Find the value of A

Because the area is 20, a = 10 or - 10
I drew the picture myself

In the rectangular coordinate system, make a straight line L through point P (2,1) to minimize the triangular area s surrounded by the positive direction of L and the two coordinate axes, and calculate the value of this area

Let l be Y-1 = K (X-2),
Therefore, the intersection of L and the two coordinate axes is (0,1-2k), (2-1 / K, 0),
So 1-2k > 0, 2-1 / k > 0,
So k = 4 + 2 * root sign (- 2K * - 1 / k) = 4 + 2 root sign 2,
If and only if - 2K = - 1 / K, that is, k = - radical 2 / 2, the equal sign holds,
So the equation of L is Y-1 = - radical 2 / 2 * (X-2),

It is known that the straight line L passes through two points a (1,4) and C (- 1,0) to find the equation of the straight line L and the area s of the triangle surrounded by the straight line L and the two coordinate axes

Let the linear equation be: y = KX + B,
Substituting the coordinates of a and C for the analytical formula, the following is obtained:
①4=k＋b
②0=－k＋b
① + ②: B = 2
∴k=2
The linear equation is: y = 2x + 2,
If x = 0, y = 2
The intersection coordinates of the straight line L and the two coordinate axes are: C (- 1,0) and B (0,2)
△ BOC area s= ½× OC × OB= ½× one × 2=1