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If the perimeter of a right triangle is 5cm and the center line on the hypotenuse is 1cm, the area of this right triangle is?
The center line on the inclined edge is 1cm, so the inclined edge is 2cm long. Then set two right angle edges as a and B, a + B = 3 ① and a ^ 2 + B ^ 2 = 4 ②
A ^ 2 + B ^ 2 + 2Ab = 9 is obtained from the square of formula ①, and 2Ab = 5 is obtained by subtracting formula ②, so the triangular area s = AB / 2 = 5 / 4
The perimeter of a right triangle is 24cm, the center line of the hypotenuse is 5cm, and the area is calculated
This is called a triangle line. The length of the center line of the bevel is equal to half the length of the bevel
So the hypotenuse of this right triangle is 10cm long
Sum of two right angle sides = 24-10 = 14 (CM)
Let two right angle sides be a and B respectively, and the length of the bevel is C
Then C = 10 A + B = 14
And because of C ²= a ²+ b ²
So 2Ab = (a + b) ²- （a ²+ b ²）= ninety-six
S = 1 / 2 * AB = 96 ÷ 4 = 24 (cm2)
If the high and good midlines on the hypotenuse of a right triangle are 4.8cm and 5cm respectively, what is its area? What is the perimeter?
The length of the center line on the beveled edge is half of the length of the beveled edge, so the length of the beveled edge is 10, the area is 24, and the other two right angle edges are 6. And 8, and the perimeter is 24
One side of the triangle is 10cm long, the center line on the side is 5cm long and the perimeter is 24cm, then the area of the triangle is () A. 12cm2 B. 6cm2 C. 8cm2 D. 24cm2
∵ one side of the triangle is 10cm long, and the center line on this side is 5cm long,
The triangle is a right triangle,
Let the length of the other two right angles be a and B,
Then A2 + B2 = 102 = 100, ①
∵ I think the perimeter is 24cm,
∴a+b=14，②
From ① and ②: ab = 48,
The area of this triangle = 1
2ab=24cm2，
Therefore, D
Help each hero! The perimeter of a right triangle is 24cm, and the center line on the hypotenuse is 5cm. Calculate the area of this triangle?
The center line of the hypotenuse of a right triangle is equal to half of the hypotenuse (the diameter of the circumscribed circle of a right triangle is the hypotenuse, so the radius and half of the hypotenuse are equal to the center line length of the hypotenuse), and the hypotenuse is equal to 10cm
If one right angle side is x, the other side is (14-x) cm
X ^ 2 + (14-x) ^ 2 = 100 (Pythagorean) then X1 = 6. X2 = 8
So the area is 6 * 8 / 2 = 24 cm ^ 2
The perimeter of a right triangle is 2+ 6. If the length of the center line on the hypotenuse is 1, the area of the triangle is equal to () A. 1 B. 1 two C. 1 four D. 3 four
∵ CD is the center line on the hypotenuse of right triangle ABC,
∴AB=2CD=2，
∵ the perimeter of right triangle ABC is 2+
6，
∴AC+BC=
6，
Square of both sides: ac2 + 2Ac • BC + BC2 = 6,
From Pythagorean theorem: ac2 + BC2 = AB2 = 4,
∴2AC•BC=2，
AC × BC=1，
∴S△ABC=1
2AC × BC=1
21=1
2．
Therefore, B
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