In △ ABC, it is known that BD and CE are the midlines on both sides respectively, and BD ⊥ CE, BD = 4, CE = 6, then the area of △ ABC is equal to () A. 12 B. 14 C. 16 D. 18

In △ ABC, it is known that BD and CE are the midlines on both sides respectively, and BD ⊥ CE, BD = 4, CE = 6, then the area of △ ABC is equal to () A. 12 B. 14 C. 16 D. 18

Connect the ED as shown in the figure,
Then s quadrilateral BCDE = 1
2DB•EH+1
2BD•CH=1
2DB(EH+CH)=1
2BD•CE=12.
And ∵ CE is △ ABC center line,
∴S△ACE=S△BCE,
∵ D is the midpoint of AC,
∴S△ADE=S△EDC,
∴S△ABC=4
3S quadrilateral BCDE = 4
three × 12=16.
Therefore, C

In △ ABC, it is known that BD and CE are the midlines on both sides respectively, and BD ⊥ CE, BD = 4, CE = 6, then the area of △ ABC is equal to () A. 12 B. 14 C. 16 D. 18

Connect the ED as shown in the figure,
Then s quadrilateral BCDE = 1
2DB•EH+1
2BD•CH=1
2DB(EH+CH)=1
2BD•CE=12.
And ∵ CE is △ ABC center line,
∴S△ACE=S△BCE,
∵ D is the midpoint of AC,
∴S△ADE=S△EDC,
∴S△ABC=4
3S quadrilateral BCDE = 4
three × 12=16.
Therefore, C

Trapezoidal and triangular area formula analysis diagram

I only know the formula
However, here you are, you know, let me be the best

Divide the trapezoid in the grid into three triangles so that their area ratio is 1:2:3

According to the stem analysis, the following delimitation methods can be obtained:

The height of a triangle and a trapezoid is equal. The bottom of the triangle is 24 cm long, the upper bottom of the trapezoid is 9 cm long, and the lower bottom is 15 cm long. Who's the area of the two figures I only asked when I saw who had a large area! What do you say when you arrive? The same big as that?

Set the height to h,
Then triangle area = 24xhx1 / 2 = 12h
Trapezoidal area = (9 + 15) xhx1 / 2 = 12h,
Therefore, the area of the two figures is equal

The two diagonals of trapezoidal ABCD intersect at point E. there are several pairs of triangles with equal area in the figure

3 pairs. Because triangle ABC and triangle DBC have the same base and equal height, they are a pair
Triangle ACD and triangle abd have the same base and equal height, and are a pair
Triangle AEB and triangle Dec are obtained by subtracting the area of the same triangle ade from triangle ACD and triangle abd respectively, so they are also a pair