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The lengths of both sides of the triangle are 8 and 6 respectively. The length of the third side is a real root of the univariate quadratic equation x2-12x + 20 = 0. Find the area of the triangle
∵ x2-12x + 20 = 0 ∵ X1 = 2, X2 = 10 (1) when X1 = 2, ∵ 8-6 = 2, ∵ this triangle does not exist (2) When x2 = 10, ∵ 62 + 82 = 102 ∵ this triangle is a right triangle) ∵ s = 12 × eight × 6=24...
The lengths of the two sides of a triangle are 8 and 6 respectively. The length of the third side is a real number sum of the square of the univariate quadratic equation x - 14x + 48 = 0. Find the area of the triangle
Solve the equation
Brought into Helen's formula: triangle area s = √ [P (P-A) (P-B) (P-C)],
Where p = (a + B + C) / 2
A. B and C represent the side length of the triangle, and √ represents the root sign, that is, the root sign of all the numbers in the immediately followed brackets
Given that the two sides of the triangle are 6 and 8 respectively, find the value range of the center line X on the third side Using the judgment of congruent triangle
In triangle ABC, ab = 8, AC = 6, find the value range of midline ad on BC side
Extend ad to e so that ad = de and connect CE
Ad is the midline, so BD = CD
Angle ADB = angle EDC (opposite vertex angle)
AD＝DE
So triangle abd is all equal to triangle ECD
Thus AB = CE = 8
In triangular AEC,
CE－AC
If both sides of the triangle are 3cm and 5cm respectively, the range of the third side a is __
∵ the length of both sides of the triangle is 3cm and 5cm respectively, and the length of the third side is xcm,
According to the trilateral relationship of the triangle, it is obtained that: 5-3 ＜ x ＜ 5 + 3, that is: 2 ＜ x ＜ 8
So the answer is: 2 ＜ x ＜ 8
If the length of the bottom edge of the isosceles triangle is 5cm and the difference between the two parts of the circumference divided by the center line on one waist is 3cm, the waist length is () A. 8cm B. 2cm C. 2cm or 8cm D. None of the above is true
∵ the difference between the two parts of the circumference divided by the middle line on the waist of the isosceles triangle is 3cm,
There are two situations: ① the difference between the waist length and the bottom length of the isosceles triangle is 3cm, and ② the difference between the bottom length and the waist length is 3cm
∵ the bottom edge is 5cm long,
The waist length is 2cm or 8cm
And ∵ the sum of the two sides of the triangle is greater than the third side, but if it wants to be 2, then 2 + 2 ＜ 5 is not a triangle,
So choose a
It is known that one side of the triangle is 5cm long and the other side is 3cm long. Then the value range of the length of the third side is __
If the length of the third side is xcm, then 5-3 ＜ x ＜ 5 + 3,
That is 2cm ＜ x ＜ 8cm
Therefore, the answer is 2cm < x < 8cm
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