Draw four small triangles in the square (as shown in the figure). The area ratio of triangles I and II is 2:1; The areas of triangles III and IV are equal; The sum of the areas of triangles I, II and III is 1 4 square meters; The sum of the areas of triangles II, III and IV is 1 6 square meters; So what is the sum of the four small triangles______ Square meters

Draw four small triangles in the square (as shown in the figure). The area ratio of triangles I and II is 2:1; The areas of triangles III and IV are equal; The sum of the areas of triangles I, II and III is 1 4 square meters; The sum of the areas of triangles II, III and IV is 1 6 square meters; So what is the sum of the four small triangles______ Square meters

Let the areas of triangles I, II, III and IV be a, B, C and D respectively; According to the title:
a=2b，c=d；
a+b+c=1
4； ①
b+c+d=1
6； ②
① Can be reduced to:
3b+c=1
4，
c=1
4-3b；
② Can be reduced to:
b+2c=1
6，③
C = 1
4-3b can be obtained by substituting ③:
b+2 × （1
4-3b）=1
6，
       b+1
2-6b=1
6，
            5b=1
2-1
6，
            5b=1
3，
             b=1
15；
c=1
4-3 × one
15=1
20；
a+b+c+d，
=3b+2c，
=3 × one
15+2 × one
20，
=1
5+1
10，
=3
10 (M2);
A: the total area of the four small triangles is 3
10 square meters
So the answer is: 3
10．

Divide a triangle into three triangles of equal area. How many divisions can you think of?

As shown in the figure, it is the required drawing

As shown in the figure, please draw three line segments in △ ABC. Divide the triangle into four parts with equal area to see who has more methods

(1) As shown in Figure 1, the midpoint of each side can be connected in sequence;
(2) As shown in Figure 2, divide BC into four equal parts and connect the quartering points of BC with a respectively
(3) As shown in Figure 3, divide △ ABC into two parts with equal area, and then make the center line of two triangles to divide △ ABC into four parts with equal area
(4) Take the midpoint of BC, AB and AC, and the midpoint of D, e and f respectively, and connect ad, CE and ef

The length of the three sides of a right triangle is 3 / 7 cm, 4 / 7 cm and 5 / 7 cm respectively. What is the area of this triangle fast

Six forty-nine! The formula of multiplying the bottom by the height divided by 2!

The three sides of a right triangle are three fifths of a centimeter, four fifths of a centimeter and one centimeter respectively. How many square centimeters is the area of this triangle? On the bevel How many centimeters is your height? Extra points for doing well

2 times of triangle area ÷ bottom edge = height
Let the triangle area be x cm2
2x÷3/5=4/5
2x=12/25
x=6/25
Answer: the area is 6 / 25 cm2
Let the solution height be y cm
bottom × Height ÷ 2 = triangle area
one × x÷2=6/25
x=6/25 × 2÷1
x=12/25
Answer: the height on the bevel is 12 / 25cm

The three sides of a right triangle are 3 decimeters, 4 decimeters and 5 decimeters long respectively. How many square centimeters is the area of this triangle? How many centimeters is the height on the bevel?

It can be seen that the two right angles are 3 decimeters and 4 decimeters long respectively
Area s = 3 * 4 / 2 = 6 square decimeters
The area is also equal to the bevel multiplied by the height of the bevel divided by 2
s=5h/2=6
H = 12 / 5 decimeter